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Question #2: For the loaded truss below, find the forces in members AG, BG, and CG. 1.5 m A 2m B 2m C 2m D 30 kN 20 N 2 m

Question #2: For the loaded truss below, find the forces in members AG, BG, and CG. 1.5 m A 2m B 2m C 2m D 30 kN 20 N 2 m

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Question #2:** For the loaded truss below, find the forces in members AG, BG, and CG. **Truss Diagram:** - The truss consists of seven members arranged in a rectangular pattern with several diagonal members. - The truss has a total length of 9 meters, broken down into segments of 2 meters each (AB, BC, CD, DE). - Vertically, the truss spans 2 meters from the bottom supports (at points E and D) to the top left node (A). - A joint at the bottom left corner (G) is located 3.5 meters above the reference point, with a vertical force of 30 kN acting downward, and a horizontal force of 20 kN acting to the left. - There are also diagonal members connecting different joints (AF, BF, CE, DE). - Nodes mentioned in the question: AG, BG, and CG, where AG is a vertical segment of 1.5 m from point G to A, BG is 2 m horizontal, and CG is a diagonal member (hypotenuse). **Load Information:** - Forces applied: A vertical load of 30 kN acting downward at point A, and a horizontal load of 20 kN acting leftward from point G. **Truss Members:** - Members AG, BG, and CG are the key points of interest for determining the internal forces. The truss load must be assessed using equilibrium equations. This truss analysis will typically involve methods such as the method of joints or the method of sections to solve for the forces in these members. By equating the sum of forces in the horizontal and vertical directions, as well as the sum of moments around a particular node to zero, the internal forces can be computed accurately for this statically determinate truss.
Transcribed Image Text:**Question #2:** For the loaded truss below, find the forces in members AG, BG, and CG. **Truss Diagram:** - The truss consists of seven members arranged in a rectangular pattern with several diagonal members. - The truss has a total length of 9 meters, broken down into segments of 2 meters each (AB, BC, CD, DE). - Vertically, the truss spans 2 meters from the bottom supports (at points E and D) to the top left node (A). - A joint at the bottom left corner (G) is located 3.5 meters above the reference point, with a vertical force of 30 kN acting downward, and a horizontal force of 20 kN acting to the left. - There are also diagonal members connecting different joints (AF, BF, CE, DE). - Nodes mentioned in the question: AG, BG, and CG, where AG is a vertical segment of 1.5 m from point G to A, BG is 2 m horizontal, and CG is a diagonal member (hypotenuse). **Load Information:** - Forces applied: A vertical load of 30 kN acting downward at point A, and a horizontal load of 20 kN acting leftward from point G. **Truss Members:** - Members AG, BG, and CG are the key points of interest for determining the internal forces. The truss load must be assessed using equilibrium equations. This truss analysis will typically involve methods such as the method of joints or the method of sections to solve for the forces in these members. By equating the sum of forces in the horizontal and vertical directions, as well as the sum of moments around a particular node to zero, the internal forces can be computed accurately for this statically determinate truss.
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