QUESTION 2 Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: DE dA = %3D EA = || E0 Since, its the line charge we use the area of a cylinder surrounding the line charge E*2 TT L= But all the charged get enclosed by the cylinder area, so denc = Q Deriving, we get: E = (1/2 TE0 )*(| IrL)
QUESTION 2 Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: DE dA = %3D EA = || E0 Since, its the line charge we use the area of a cylinder surrounding the line charge E*2 TT L= But all the charged get enclosed by the cylinder area, so denc = Q Deriving, we get: E = (1/2 TE0 )*(| IrL)
Related questions
Question
FILL IN THE BLANKS
![QUESTION 2
Find the electric field everywhere of an infinite uniform line charge with total charge Q.
Sol.
Using Gauss's Law:
DE dA
%3D
EA =
| E0
Since, its the line charge we use the area of a cylinder surrounding the line charge
E*2 TT
L=
But all the charged get enclosed by the cylinder area, so
denc
= Q
Deriving, we get:
E = (1/2 TE0 )*(|
IrL)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F939ae955-a705-4ee0-830e-65a71a6470f9%2Ff06edacb-759e-4d57-b9e5-9990baaa6552%2Fmgnionk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 2
Find the electric field everywhere of an infinite uniform line charge with total charge Q.
Sol.
Using Gauss's Law:
DE dA
%3D
EA =
| E0
Since, its the line charge we use the area of a cylinder surrounding the line charge
E*2 TT
L=
But all the charged get enclosed by the cylinder area, so
denc
= Q
Deriving, we get:
E = (1/2 TE0 )*(|
IrL)
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)