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Question 2 Consider a planet orbiting its star at some distance. What surface temperature do you expect if that the planet has no atmosphere? You can assume: • radiant flux Fsolar: 4,737 VW per square meter (directly looking at the star) star/planet distance d: 298,133,550,850 m • planet radius r: 7,155 yd • surface heat capacity Cp: 94,401,614 J/K per square meter planetary albedo a: 0.3 • surface emissivity e: 0.69 We expect your answer in degree C with one significant digit. (In the next question you will be asked to explain how you arrived at your solution)

Question 2 Consider a planet orbiting its star at some distance. What surface temperature do you expect if that the planet has no atmosphere? You can assume: • radiant flux Fsolar: 4,737 VW per square meter (directly looking at the star) star/planet distance d: 298,133,550,850 m • planet radius r: 7,155 yd • surface heat capacity Cp: 94,401,614 J/K per square meter planetary albedo a: 0.3 • surface emissivity e: 0.69 We expect your answer in degree C with one significant digit. (In the next question you will be asked to explain how you arrived at your solution)

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Question 2 Consider a planet orbiting its star at some distance. What surface temperature do you expect if that the planet has no atmosphere? You can assume: • radiant flux Fsolar: 4,737 W per square meter (directly looking at the star) star/planet distance d: 298,133,550,850 m planet radius r: 7,155 yd • surface heat capacity Cp: 94,401,614 J/K per square meter planetary albedo a: 0.3 • surface emissivity e: 0.69 We expect your answer in degree C with one significant digit. (In the next question you will be asked to explain how you arrived at your solution)
Transcribed Image Text:Question 2 Consider a planet orbiting its star at some distance. What surface temperature do you expect if that the planet has no atmosphere? You can assume: • radiant flux Fsolar: 4,737 W per square meter (directly looking at the star) star/planet distance d: 298,133,550,850 m planet radius r: 7,155 yd • surface heat capacity Cp: 94,401,614 J/K per square meter planetary albedo a: 0.3 • surface emissivity e: 0.69 We expect your answer in degree C with one significant digit. (In the next question you will be asked to explain how you arrived at your solution)
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