Question 2: Conducting sphere in a uniform Electric Field by method of images. We consider a conducting sphere of radius a = 1m in a uniform electric field E0= 1000 V/m. A uniform field can be thought of as being produced by appropriate positive and negative charges at infinity. << = Q/4 TEO (2+R2+2rR cos 0) 1/2 Q/4 πTEO (2 R2 2rR cos 0)1/2 - aQ/4πEO a4 2a²r aQ/4πEO 1/2 Rr² + + R2 R a4 2a²r cos R2+ - R2 R cos 8 $ = Απερ 1414 - 20 cos 0 + 2Q a³ r R² +20% cos 0] + +... (2.12) 1/2 (2.13) where the omitted terms vanish in the limit R. In that limit 2Q/4TER² becomes the applied uniform field, so that the potential is - Eo(r-2) cos 0 $ = − ] (2.14) 1) Give the derivation process of eq (2.12) 2) Plot the distributions of the potential and current density vector. 3) Compare the results from eq(2.12) and eq(2.14) as R varies.

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Question 2:
Conducting sphere in a uniform Electric Field by method of images.
We consider a conducting sphere of radius a = 1m in a uniform electric field E0= 1000 V/m. A
uniform field can be thought of as being produced by appropriate positive and negative charges
at infinity.
<< =
Q/4 TEO
(2+R2+2rR cos 0) 1/2
Q/4 πTEO
(2 R2 2rR cos 0)1/2
-
aQ/4πEO
a4 2a²r
aQ/4πEO
1/2
Rr² + +
R2 R
a4 2a²r
cos
R2+
-
R2 R
cos 8
$ =
Απερ
1414 - 20 cos 0 +
2Q a³
r
R²
+20% cos 0] +
+...
(2.12)
1/2
(2.13)
where the omitted terms vanish in the limit R. In that limit 2Q/4TER²
becomes the applied uniform field, so that the potential is
- Eo(r-2) cos 0
$ = − ]
(2.14)
1) Give the derivation process of eq (2.12)
2) Plot the distributions of the potential and current density vector.
3) Compare the results from eq(2.12) and eq(2.14) as R varies.
Transcribed Image Text:Question 2: Conducting sphere in a uniform Electric Field by method of images. We consider a conducting sphere of radius a = 1m in a uniform electric field E0= 1000 V/m. A uniform field can be thought of as being produced by appropriate positive and negative charges at infinity. << = Q/4 TEO (2+R2+2rR cos 0) 1/2 Q/4 πTEO (2 R2 2rR cos 0)1/2 - aQ/4πEO a4 2a²r aQ/4πEO 1/2 Rr² + + R2 R a4 2a²r cos R2+ - R2 R cos 8 $ = Απερ 1414 - 20 cos 0 + 2Q a³ r R² +20% cos 0] + +... (2.12) 1/2 (2.13) where the omitted terms vanish in the limit R. In that limit 2Q/4TER² becomes the applied uniform field, so that the potential is - Eo(r-2) cos 0 $ = − ] (2.14) 1) Give the derivation process of eq (2.12) 2) Plot the distributions of the potential and current density vector. 3) Compare the results from eq(2.12) and eq(2.14) as R varies.
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