QUESTION 2 Benzene freezes at 5.5°C under 1 atm. The density of benzene is 0.879 g/cm³ in liquid form and 0.891 g/cm³ in solid form. Its enthalpy of fusion is 10.59 kJ/mol. Estimate the new freezing point of benzene (°C) when pressure increase by 1300 atm. Instruction: Please round to 2 decimal places For example, 10.564 is written as 10.56. Hint: Follow the procedures of homework 4 question #4, but there are some differences: (1) You need to calculate the molar volume (unit: m³/mol) using molar mass of benzene devided by its density (pay attention to the unit which should be m3/mol), then calcualte Atrs using molar volume of liquid minus molar volume of solid (2) AtrsS can be calcualte using AfusH/T, where the unit of AfusH needs to be J/mol not kJ/mol. (3) after AT is calculated, you need to add the original freezing point to get the new freezing point.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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QUESTION 2
Benzene freezes at 5.5°C under 1 atm. The density of benzene is 0.879 g/cm³ in liquid form and 0.891 g/cm³ in solid form. Its
enthalpy of fusion is 10.59 kJ/mol. Estimate the new freezing point of benzene (°C) when pressure increase by 1300 atm.
Instruction: Please round to 2 decimal places For example, 10.564 is written as 10.56.
Hint: Follow the procedures of homework 4 question #4, but there are some differences: (1) You need to calculate the molar volume
(unit: m³/mol) using molar mass of benzene devided by its density (pay attention to the unit which should be m³/mol), then calcualte
Atrs using molar volume of liquid minus molar volume of solid (2) AtrsS can be calcualte using AfusH/T, where the unit of AfusH
needs to be J/mol not kJ/mol. (3) after AT is calculated, you need to add the original freezing point to get the new freezing point.
Transcribed Image Text:QUESTION 2 Benzene freezes at 5.5°C under 1 atm. The density of benzene is 0.879 g/cm³ in liquid form and 0.891 g/cm³ in solid form. Its enthalpy of fusion is 10.59 kJ/mol. Estimate the new freezing point of benzene (°C) when pressure increase by 1300 atm. Instruction: Please round to 2 decimal places For example, 10.564 is written as 10.56. Hint: Follow the procedures of homework 4 question #4, but there are some differences: (1) You need to calculate the molar volume (unit: m³/mol) using molar mass of benzene devided by its density (pay attention to the unit which should be m³/mol), then calcualte Atrs using molar volume of liquid minus molar volume of solid (2) AtrsS can be calcualte using AfusH/T, where the unit of AfusH needs to be J/mol not kJ/mol. (3) after AT is calculated, you need to add the original freezing point to get the new freezing point.
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