QUESTION 2: A part of the phase diagram of X and Y elements that can be mixed isomorphically is given above. 1300 SIVI Alloy at point A; It contains 35% X and 65% Y and is 1250 oC. a) Calculate the percentage of liquid and solid phases of the alloy at SVI point A. b) Calculate the ratio of X and Y in% of the liquid and solid phases of 1200 the alloy at point A. 20 30 40 50 31 35 42

Calculate the IPF for UO, which has the CaF, structure shown in the figure below F ions located at corners of a cube (at one-quarter of the distance along the body diagonal) O Ca?+ (a) (b) Structure: fluorite (CaF2) type Bravais lattice: fce Ions/unit cell: 4Ca2++ 8F Typical ceramics: U0, ThO, and TeO Express your answer to three significant figures. A2 vec ? IPF = Submit

at is the composition, in weight percent, of an alloy that consists of 94.1 at% Ag and 5.9 at% Cu? The atomic weights for Ag and Cu are 107.87 g/mol and 63.55 g/mol, respectively A. 9.6 wt% Ag and 90.4 wt% Cu B. 90.4 wt% Ag and 9.6 wt% Cu C. 3.6 wt% Ag and 96.4 wt% Cu D. 96.4 wt% Ag and 3.6 wt% Cu

GaAs, has the zincblende crystal structure. The lattice parameter is a = 5.653 Å.1) Calculate the shortest Ga-As distance and2) the shortest Ga-Ga distance.3) According to the periodic table, Ga covalent radius is 1.26 Å, and As covalentradius is 1.20 Å; what is the atomic packing factor for GaAs?

* .Refractories are of the . . ceramic types ........ advanced traditional ...Electrical conductivity of Ceramics is low because valence electrons are locked in bonds between atoms. they have a wide electron bands. they are electropositive. ons are rarely joined edge to edge, and never face to * .face, but always share the corners Because of the high charge on the Si+4 ion. Because of the low electronegativity of Si atom.

Fe has both bcc and fcc structures with difference lattice constants: the bcc lattice constant a = 2.8664 Angstrom; and the fcc lattice constant = 3.6468 Angstrom. If we treat Fe atoms as touching hard spheres, (1) Derive associated atomic radius of Fe atoms in the bcc structure (2) Derive associated atomic radius of Fe atoms in the fcc structure (3) Calculate the volume fraction of Fe atoms in the bcc structure (4) Calculate the volume fraction of Fe atoms in the fcc structure (5) Calculate the edge lengths of octahedral and tetrahedral interstitials in bcc Fe (6) Calculate the edge lengths of octahedral and tetrahedral interstitials in fcc Fe (7) The fcc Fe has a denser packed structure yet solubility of carbon (atomic radius 0.7 Angstrom, only can occupy the interstitial sites of Fe) is much higher than that in the bcc Fe. Why is it so?

Dolomite has a very similar structure in which Mg substitutes for Ca in alternatinglayers. Assume that Ca2+ has an ionic radius of 100 picometers and Mg2+ has anionic radius of 72 picometers. Using your knowledge of crystal chemistry, would youexpect significant substitution of Mg for Ca in calcite or Ca in the Mg site indolomite?

As minerals were formed from the molten magma, different ions occupied the same cites in the crystals. Lithium often occurs along with magnesium in minerals despite the difference in the charge on their ions. Suggest an explanation.

Need asap show detailed solution with explanation on how u get the answer in each step

Calculate the concentration of vacancies in copper at room temperature (25 °C). What temperature will be needed to heat treat copper such that the concentration of vacancies produced will be 1000 times more than the equilibrium concentration of vacancies at room temperature? Assume that 20,000 cal are required to produce a mole of vacancies in copper. The lattice parameter of FCC copper is 0.36151 nm.