Question 2 1 pts For the same curve as above, x(t) = t cos(t/2), y(t) = t², z(t) = t sin(t/2), a student remembers the first year formula a = dv/dt and so tries to calculate the scalar acceleration a by calculating the derivative of the speed v. At time t = 3.19, let A be the percent error, the absolute value of the difference between this wrong calculation and the correct answer divided by the correct answer times 100. Then sin(A/2) is 0.772 -0.339 0.968 0.902 -0.048 0.711 0.442 -0.271

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
icon
Related questions
Question
Question 2
1 pts
For the same curve as above,
x(t) = t cos(t/2),
y(t) = t²,
z(t) = t sin(t/2),
a student remembers the first year formula a = dv/dt and so tries to calculate the
scalar acceleration a by calculating the derivative of the speed v. At time t = 3.19,
let A be the percent error, the absolute value of the difference between this wrong
calculation and the correct answer divided by the correct answer times 100. Then
sin(A/2) is
0.772
-0.339
0.968
0.902
-0.048
0.711
0.442
-0.271
Transcribed Image Text:Question 2 1 pts For the same curve as above, x(t) = t cos(t/2), y(t) = t², z(t) = t sin(t/2), a student remembers the first year formula a = dv/dt and so tries to calculate the scalar acceleration a by calculating the derivative of the speed v. At time t = 3.19, let A be the percent error, the absolute value of the difference between this wrong calculation and the correct answer divided by the correct answer times 100. Then sin(A/2) is 0.772 -0.339 0.968 0.902 -0.048 0.711 0.442 -0.271
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer