AQuestion 24Find out which one from L of the following statements are TRUE or FALSE.1. Stack pointer is the register that hold the address of the current instruction being executed.2. Parallel hardware cannot be used for faster division because subtraction is conditional on sign ofremainder.3. Million instructions per second (MIPS) is not an accurate performance metric.4. Floating-Point representation allows much larger range with increased accuracy.5. Opcode, funct3 and funct7/6 in instruction format are used to identify the instruction.6. The compiler is used to transfer the assembly language program into the machine language.

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Answered: Question 2 1 1 : Find out which one…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Part 1: Preliminary Summarize the difference between binary machine language, assembly language, and high-level source files like C. Contrast the difference between a compiler, assembler, and linker What is the difference between the data segment and the text segment of in an assembly language program? What register is used as the stack pointer? What is a ebreak instruction in the sample program? How would you define a constant named 'BLUE' and assign it to the value OX00F in assembly language? Describe how to implement the psuedo-instruction li t1, e using a native instruction.
1)Write the following code segment in MARIE assembly and test it. int x, y; scanf(“%d”, &x); If ( x > 1) { y = x + x; x = 0; } y = y + 1; printf(“%d”, y); exit(0);
Indicate in the table below if the instruction memory, data memory, or the immediate generation (sign-extend) unit are active for the given instructions. If the element is active for the given instruction, put an ‘X’ in the corresponding field. If not, leave the field blank.
Translate the following C code to MIPS assembly, assuming that the variables f, g, h, i, and j correspond to registers $50, $s1, $s2, $s3, and $54 respectively. Also, assume that the base addresses of arrays A and B are contained in $56 and $s7 respectively, and that each element of arrays A and B are 4-byte words: B[8] =A[i] + A[j]; Which of the following MIPS assembly code snippets correctly performs the above operation? sll $t1, $s3, 2; add $t1, $56, $t1; lw $12, 0($t1); sll $t1, $s4, 2; add $11, $s6, St1; lw $13, 0($t1); add $12, $12, $t3; sw $12, 32($s7) sll $t1, $s3, 2; add $11, $s6, $t1; lw $12, 0($t1); sll $t1, $s4, 2; add $11, $s6, $t1; lw $13, 0($t1); add $t4, $12, $t3; sll $15, $t0, 2; add $15, $s7, $15; sw $t4, 32($15) Iw $11,0($s3); Iw $12, 0($s4); add $13, $11, $12; sw $13, 32($s7) sll $t1, $s3, 2; lw $12, 0($t1); sll $t1, $s4, 2; lw $13, 0($t1); add $t4, $t2, $t3; sw $t4, 32($s7)
answer with proper explanation and step by step solution. The instruction is to use a "loop" to write the MIPS code for this.
PLEASE HELP
Because of this, the means by which one instruction acquires its input data are independent of the means by which another acquires its data. When used with a(n): A Combining sets of data with sets of instructions B An example of "multiple data, multiple instruction" C D is for "data alone," meaning there is just one instruction. One order, several results
In generall, computers think in terms of numbers (i.e. binary data). Thus, any operation performed in the computer must be done using either mathematical or logical operations. Given this inherit limitation of computers, what is the compare instruction actually doing when we, as assembly programmers, provide two numbers for it to "compare"? Furthermore, what assembly instruction is similar to the compare instruction? How are the two instructions different?
Computer Science
Convert the given hex value to its R-format MIPS instruction by completing the following table. The instruction and letters for registers must be in lower case. DO NOT TYPE DOLLAR SIGNS WITH REGISTERS. Hex Opcode (decimal) rs (decimal) rt (decimal) rd (decimal) funct (decimal) Instruction 02488822 O 18 16 17 34 sub s4 $$1 " $ to " LA
Can you explain please
In assembly 68k write the: Initialize the supervisor stack pointer to $8000 Initialize the program counter to $1000 Reserve locations at $2000 to hold your first name only (Joshua) as text and call it NAM Reserve locations at $3000 to store 9 longwords, call it MEM, and write your family name (Kimmich) as a comment Reserve locations at $12400 to store 32-bit unsigned integer variable called RES (to be computed)

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