Question 18 of 31 How many atoms of mercury are required to produce 3.49 L of H2 gas (density = 0.0899 g/L ) according to the balanced chemical reaction: 2 Hg(1) + 2 HNO:(aq)Hg:(NO.):(aq) + H:(g) 0.0899 1 g H: ADD FACTOR DELETE ANSWER RESET (), げ 525.2 1 2.02 1.87 x 1023 1.87 63.01 2 1.01 9.42 x 1020 7.20 x 1020 9.35 x 1022 3.49 0.0899 200.6 6.022 x 1023 g Hg:(NOs)2 mol Hg mol Hg:(NOs): g H: g H:/L atoms Hg mol Ha mol HNO. L H2 g HNO,

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Question 18 of 31**

**Problem Statement:**  
How many atoms of mercury are required to produce 3.49 L of H₂ gas (density = 0.0899 g/L) according to the balanced chemical reaction:

2 Hg(l) + 2 HNO₃(aq) → Hg₂(NO₃)₂(aq) + H₂(g)

**Solution Process:**

1. The equation provided shows the relationship between mercury and hydrogen gas.
2. The density of H₂ gas is 0.0899 g/L. Given volume of H₂ gas is 3.49 L.

**Calculation Steps:**

- Use the density to convert the volume of hydrogen gas to mass:
  \( \text{Mass of H₂} = \text{Volume} \times \text{Density} = 3.49 \, \text{L} \times 0.0899 \, \text{g/L} \)

- Use stoichiometry to determine the amount of mercury required.

**Interface Description:**

- The screen displays input fields for density in g/L and volume in L.
- A graphical setup shows a multiplication chain to calculate necessary conversions.
- Options to add, delete, or reset calculation factors for flexibility.

**Result:**

- Utilizing stoichiometric calculations based on provided reaction and given density and volume, calculate the precise number of mercury atoms involved.

This process demonstrates an application of stoichiometry and density concepts to solve a chemical quantity problem.
Transcribed Image Text:**Question 18 of 31** **Problem Statement:** How many atoms of mercury are required to produce 3.49 L of H₂ gas (density = 0.0899 g/L) according to the balanced chemical reaction: 2 Hg(l) + 2 HNO₃(aq) → Hg₂(NO₃)₂(aq) + H₂(g) **Solution Process:** 1. The equation provided shows the relationship between mercury and hydrogen gas. 2. The density of H₂ gas is 0.0899 g/L. Given volume of H₂ gas is 3.49 L. **Calculation Steps:** - Use the density to convert the volume of hydrogen gas to mass: \( \text{Mass of H₂} = \text{Volume} \times \text{Density} = 3.49 \, \text{L} \times 0.0899 \, \text{g/L} \) - Use stoichiometry to determine the amount of mercury required. **Interface Description:** - The screen displays input fields for density in g/L and volume in L. - A graphical setup shows a multiplication chain to calculate necessary conversions. - Options to add, delete, or reset calculation factors for flexibility. **Result:** - Utilizing stoichiometric calculations based on provided reaction and given density and volume, calculate the precise number of mercury atoms involved. This process demonstrates an application of stoichiometry and density concepts to solve a chemical quantity problem.
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