Question 15. Similar to the previous question, let 61, 62 be the estimate for ẞ1, B2 in the simple model Y = B1 + ẞ2x + €. Let the y-transformation be Y New = Cy = Cx + x. The new estimates 6 New, 6 New xNew (a) New = Cy+ ₁ and Ne = 162 (b) New = Cy+61 and 6 New = are given by: Y and the x-transformation be (c) New = Cy+b2cx + ô₁ and ô New = cxb2 Cx New = b₂ (d) b¥ew = Cy – Özca + bi and bye (e) ĥ New = Cy + √2Cx − ô₁ and ĥ New = ô₂ + Cy
Question 15. Similar to the previous question, let 61, 62 be the estimate for ẞ1, B2 in the simple model Y = B1 + ẞ2x + €. Let the y-transformation be Y New = Cy = Cx + x. The new estimates 6 New, 6 New xNew (a) New = Cy+ ₁ and Ne = 162 (b) New = Cy+61 and 6 New = are given by: Y and the x-transformation be (c) New = Cy+b2cx + ô₁ and ô New = cxb2 Cx New = b₂ (d) b¥ew = Cy – Özca + bi and bye (e) ĥ New = Cy + √2Cx − ô₁ and ĥ New = ô₂ + Cy
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:Question 15. Similar to the previous question, let 61, 62 be the estimate for ẞ1, B2 in the simple
model Y = B1 + ẞ2x + €. Let the y-transformation be Y New = Cy
= Cx + x. The new estimates 6 New, 6 New
xNew
(a) New
=
Cy+ ₁ and Ne
=
162
(b) New
=
Cy+61 and 6 New
=
are given by:
Y and the x-transformation be
(c) New = Cy+b2cx + ô₁ and ô New = cxb2
Cx
New
=
b₂
(d) b¥ew = Cy – Özca + bi and bye
(e) ĥ New = Cy + √2Cx − ô₁ and ĥ New = ô₂ + Cy
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