Question 12 WA 5.00 g-sample of KOH(s) at 25.0°C was added to 100.0 g of H2O(1) at room temperature inside an insulated cup calorimeter, and the contents were stirred. After all the KOH(s) dissolved, thetemperature of the solution had increased. Based on the information given, which of the following best justifies the claim that the dissolution of KOH(s) is a thermodynamically favorable process?The forces between the ions and the water molecules are strọnger than the forces between water molecules, thus AH < 0. Also, the ions become less dispersed as KOH(s) dissolves, thusAS >0. Therefore, AG < 0.less than that released as the ion-dipole attractions form during solvation, thus AH < 0. Also, the ions become moreThe energy required to break the bonds between the ions in the solidwidely dispersed as KOH(s) dissolves, thus AS > 0. Therefore, AG < 0.The average kinetic energy of the particles increases, resulting in AH > 0. Also, the ions become more widely dispersed as KOH(s) dissolves, thus AS > 0. Therefore. AG > 0.DThe average kinetic energy of the particles increases, resulting in AH > 0. Also, the ions become more widely dispersed as KOH(s) dissolves, thus AS < 0. Therefore. AG > 0.escQ Search or enter website name@#$%&

Since temperature of the solution is increased means energy is released during dissolution process…

Question 12W A 5.00 g-sample of KOH(s) at 25.0 C was added to 100.0 g of H2O(1) temperature of the solution had increased. Based on the information given, which of the following best justifies the claim that the dissolution of KOH(s) is a thermodynamically favorable process? room temperature inside an insulated cup calorimeter, and the contents were stirred. After all the KOH(s) dissolved, the The forces between the ions and the water molecules are strọnger than the forces between water molecules, thus AH < 0. Also, the ions become less dispersed as KOH(s) dissolves, thus A AS >0. Therefore, AG < 0. The energy required to break the bonds between the ions in the solid is less than that released as the ion-dipole attractions form during solvation, thus AH < 0. Also, the ions become more B widely dispersed as KOH(s) dissolves, thus AS > 0. Therefore, AG < 0. The average kinetic energy of the particles increases, resulting in AH >0. Also, the ions become more widely dispersed as KOH(s) dissolves, thus AS > 0. Therefore, AG > 0. The average kinetic energy of the particles increases, resulting in AH >0. Also, the ions become more widely dispersed as KOH(s) dissolves, thus AS < 0. Therefore, AG > 0. D

Question 12W A 5.00 g-sample of KOH(s) at 25.0 C was added to 100.0 g of H2O(1) temperature of the solution had increased. Based on the information given, which of the following best justifies the claim that the dissolution of KOH(s) is a thermodynamically favorable process? room temperature inside an insulated cup calorimeter, and the contents were stirred. After all the KOH(s) dissolved, the The forces between the ions and the water molecules are strọnger than the forces between water molecules, thus AH < 0. Also, the ions become less dispersed as KOH(s) dissolves, thus A AS >0. Therefore, AG < 0. The energy required to break the bonds between the ions in the solid is less than that released as the ion-dipole attractions form during solvation, thus AH < 0. Also, the ions become more B widely dispersed as KOH(s) dissolves, thus AS > 0. Therefore, AG < 0. The average kinetic energy of the particles increases, resulting in AH >0. Also, the ions become more widely dispersed as KOH(s) dissolves, thus AS > 0. Therefore, AG > 0. The average kinetic energy of the particles increases, resulting in AH >0. Also, the ions become more widely dispersed as KOH(s) dissolves, thus AS < 0. Therefore, AG > 0. D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

6. For a chemical reaction of: 3A + B 2C at 310 K for the initial conditions of: [A] = 25 mM, [B] = 52 mM, [C] = 13 mM with %3D H = 7.27 kJ/mole, u, =8.34 kJ/mole, 4 = 0.56 kJ/mole Calculate the value of AG for this process. Calculate the value of AG for this process. (A) (B) (C) Calculate K, for this process. (D) Will this reaction spontaneously proceed in the forward or reverse direction? Why?
1. Consider the reaction: A 2 B, where Keg 1.33 x 10-1. (a) What is the AGº' for this reaction? (b) If the reaction above is initially at standard-state conditions, what are the concentrations of A and B once equilibrium is reached?
For a certain reaction, AGxn = +3.5 kJ/mol at 298 K. %3! a. If this reaction is at equilibrium, which would you expect to have higher concentra- tions: reactants or products?
Consider the dissolution of nitrous acid: HNO₂(aq) For this reaction under standard conditions, AG° = 19.1 kJ/mol. Calculate A Gat 298 K, when [H*] = 5.0×10-² M, [NO₂¯] = 2.0×10−³ M and [HNO₂] = 0.10 M. (A) 2.0 kJ/mol (B) 12.5 kJ/mol (C) 16.6 kJ/mol (D) 19.1 kJ/mol (E) 36.2 kJ/mol - H+ (aq) + NO₂ (aq).
For a particular reaction △H= -32 kJ and △S = -98J/K (A) At what temp will the reaction be at equilibrium ? (B) If the temperature is increased from the equilibrium temperature what will happen?
Calculate the AH°, AS°, and AG° at 298 K for the following reaction: (Use the values found in Thermodynamic Properties to calculate your answers for questions a and b.) Al2O3(s) + 3 C(graphite) + 3 Cl₂(g) → 2 AICI 3(s) + 3 CO(g) 4.0 -64 a) ΔΗΟ kJ/mol b) AS° ✓ J/K.mol kJ/mol (Determine from the temperature, AH and AS) c) AGO 4.0 76.9 4.0 -89 (d) Is the reaction extensive at standard conditions and 298 K? O Yes O NO (e) Write the expression for K. (Format example: Kp = pHC12 / pH₂. pCl₂ would be entered as K_{p} = pHCI^{2}/pH_{2}. pCl_{2}.) Help chemPad XX (PCO)3 (pCl₂)³ ← Greek (PCO)^3/(pCl_2)^3 Your answer provides a different type of equation than was expected. (f) Calculate the value of K at 298 K 2.51e-16 X (Please answer to 3 significant figures.) (g) Estimate the value of K at 600 K. 1.79e-8 X (Please answer to 3 significant figures.)
38. For this process at 25 °C: H2O(g) H2O (A) AH is negative as energy is released. (B) AH is negative as energy is absorbed. (C) AH is positive as energy is released. (D) AH is positive as energy is absorbed.
Consider the reaction 12(g) + Cl₂(g) 2ICI(g) Use the standard thermodynamic data in the tables linked above. Calculate AG for this reaction at 298.15K if the pressure of ICI(g) is reduced to 16.66 mm Hg, while the pressures of l2(g) and Cl₂(g) remain at 1 atm. kJ/mol ANSWER: (Please type answer).
One of the reactions that destroys ozone in the upper atmosphere is NO(g) + O3(g) ⇒ NO2 (g) + O2(g) Substance and State AGf (kJ/mol) NO(g) 87 NO₂(g) 52 0₂ (9) 0 03 (9) 163 a Calculate ΔG° (at 298 K) for this reaction. AG = -198 kJ b Calculate K (at 298 K) for this reaction. K =