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Question #11 What is the ratio of the root-mean-square velocities (Urms): (ratio = urms O2: Ums Xe) ? of oxygen (O2) molecules to that of xenon atoms (Xe) • at 323 K O ratio of effusion of O2: Xe = 4.103 O ratio of effusion of O2: Xe = 1.002 O ratio of effusion of 02: Xe = 2.026 O ratio of effusion of 02 :Xe = 20.03

Question #11 What is the ratio of the root-mean-square velocities (Urms): (ratio = urms O2: Ums Xe) ? of oxygen (O2) molecules to that of xenon atoms (Xe) • at 323 K O ratio of effusion of O2: Xe = 4.103 O ratio of effusion of O2: Xe = 1.002 O ratio of effusion of 02: Xe = 2.026 O ratio of effusion of 02 :Xe = 20.03

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Gram's Law of Effusion: rate of effusion MM rate effusion A MMB rate effusion B { I MMA 3RT Hrms = { MM Urms = root mean square velocity ( Hrms ) of a gas molecule in meters/sec • R = 8.31 (kg - m2 )/(s² - mol-K) Ideal Gas Constant in SI units • MM = molar mass - kg/mol in SI units ~ 02 = 0.03200 kg/mol Question #11 What is the ratio of the root-mean-square velocities (ums): (ratio = urms 02: Urms Xe) ? • of oxygen (02) molecules to that of xenon atoms (Xe) • at 323 K O ratio of effusion of O2: Xe e = 4.103 O ratio of effusion of O2: Xe = 1.002 O ratio of effusion of 02 :Xe = 2.026 O ratio of effusion of 02 :Xe = 20.03
Transcribed Image Text:Gram's Law of Effusion: rate of effusion MM rate effusion A MMB rate effusion B { I MMA 3RT Hrms = { MM Urms = root mean square velocity ( Hrms ) of a gas molecule in meters/sec • R = 8.31 (kg - m2 )/(s² - mol-K) Ideal Gas Constant in SI units • MM = molar mass - kg/mol in SI units ~ 02 = 0.03200 kg/mol Question #11 What is the ratio of the root-mean-square velocities (ums): (ratio = urms 02: Urms Xe) ? • of oxygen (02) molecules to that of xenon atoms (Xe) • at 323 K O ratio of effusion of O2: Xe e = 4.103 O ratio of effusion of O2: Xe = 1.002 O ratio of effusion of 02 :Xe = 2.026 O ratio of effusion of 02 :Xe = 20.03
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