Question 10) Sasha pushes a 15 kg cart full of donated books through a 5.0 m fong starting area. The cart is then released and must reach the top of the hill 2.5 m in height, as shown in the diagram below. He must apply enough force on the cart so that the cart is able to travel along the 8.0 m path and reach the top of the hill. The force of friction between the 8.0 m path and the cart is 11.0 N. What minimum force on the cart in the starting area is required to get it to the top of the hill? Stopping point 8.0 m 2.5 m Mass 15 kg 5.0 m Starting area

Question 10) Sasha pushes a 15 kg cart full of donated books through a 5.0 m fong starting area. The cart is then released and must reach the top of the hill 2.5 m in height, as shown in the diagram below. He must apply enough force on the cart so that the cart is able to travel along the 8.0 m path and reach the top of the hill. The force of friction between the 8.0 m path and the cart is 11.0 N. What minimum force on the cart in the starting area is required to get it to the top of the hill? Stopping point 8.0 m 2.5 m Mass 15 kg 5.0 m Starting area

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: An object of mass m is at rest at the top of a smooth slope of height h and length L. The…

A: Total energy of the system at top point is due to the gravity. And just before reaching the bottom…

Q: A child and sled with a combined mass of 53.9 kg slide down a frictionless slope. If the sled starts…

Q: A small block is sent through point A with a speed of 11 m/s, as shown in the figure. Its path is…

Q: A daredevil on a motorcycle leaves the end of a ramp with a speed of 38.9 m/s as in the figure…

A: KEBottom-KEtop=PE0.5mvbottom2-0.5mvtop2=mghh=0.vbottom2-0.5vtop2g

Q: A hand pushes a 10 kg block along a table from point A to point C as shown in the figure below. The…

Q: A stunt woman (m= 67.0 kg) on a movie set is getting readyto jump off a building. She is wearing a…

Q: A 250g PASCar drags a sliding tray of 50g on the track. The kinetic friction coefficient between the…

Q: A 400 kg kg roller coaster starts from 2.0 m/s at point A. Assume that friction and air resistance…

A: Given data: Mass (m) = 400 kg Velocity at point A (v) = 2.0 m/s Air resistance and friction force…

Q: A 150 N force acting along an incline is pushing a 6.50 kg object 4.65 m up a 20.0 degree incline.…

A: Analyze the free body diagram. Consider the rightward direction along the incline plane to be…

Q: A box slides from rest down a frictionless ramp inclined at 31.0° with respect to the horizontal and…

A: Given: Inclination angle is θ=31° Initially object is at rest on the top of ramp and then it slides…

Q: To enter the main pool at an amusement part, a swimmer uses a water slide which has a vertical…

Q: A daredevil on a motorcycle leaves the end of a ramp with a speed of 34.6 m/s as in the figure…

A: Initial velocity (V°) = 34.6 m)/s Final velocity (Vf) =33 m/s

Q: Solve using conservation of E. A 30.0 kg block slides 8.00 m down a ramp with a height of 4.50 m.…

A: Please see the attached images for the solution. If there are queries or if the images are not…

Q: 3. In the figure, a block slides along a track from one level to a higher level after passing…

A: To determine: A block is sliding along a track from one level to the higher level passing through an…

Q: A child slides down a snow-covered slope on a sled. At the top of the slope, her mother gives her a…

Q: A 400. kg cart slides along the track shown in the image, beginning at point A. It starts from rest…

Q: A vehicle applies it breaks for 102 ft before departing the roadway. The roadway surface friction…

Q: BOX 1.25m 34° Assuming no friction and the box starts at rest, what will be the speed of the box at…

Q: block slides down a ramp which is inclined : an angle 7°. The block has speed 3 m/s at ne top of the…

A: Given values:- Inclined angle,(θ)=7 0 -----(1) Coefficient of kinetic friction,(μk)=0.7 -----(2)…

Q: A ski starts from rest and slides down a 22-degree incline 75 m long. a) If the coefficient of…

Q: In the figure, a 4.4 kg block slides along a track from one level to a higher level after passing…

A: Given: In this question, the given values are, m=4.4 kg, vo=6.4 m/s, ∆h=1.1 m, μk=0.590. To find the…

Q: Here we go again this time, d = 4.09 m. Suppose the block starts on the track at x = 0. What minimum…

Q: A force F = (cx – 3.00x? )î acts on a particle as the particle moves along an x axis, with F in…

Q: A toy car has a friction coefficient of 0.03. On a 30 degree incline starting from rest, what…

A: This is a question regarding to the motion of a body under gravity. The figure for the problem can…

Q: Provide drawings and figures in the solution of the following problems: Awooden block slides upward…

A: The final velocity of an object v after traveling a distance s and starting with the initial…

Q: Sled A and sled B, whose masses are 43.6kg and 87.2kg respectively, are attached by a massless bar.…

A: Draw the free-body diagram of sled A.

Concept explainers

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest. 

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

5. A top WNBA player can jump about .7 meters off the ground. If her mass is 50 kg, what force must she exert against the ground? Assume she crouches a distance of .2 metes prior to jumping, and thus the upward force has this distance to act before leaving the ground. 6. A block is given an initial speed of 4 meters per second up the 0 = 22° plane shown below. Ignoring friction, %3D (a) how far up the plane will it go? (b) How much time elapses before it returns to its starting point? R 4m/s s 22°
previous problem: A small block slides down a frictionless track whose shape is described by y = (x^2) /d for x<0 and by y = -(x^2)/d for x>0. The value of d is 3.85 m, and x and y are measured in meters as usual. Suppose the block starts from rest on the track, at x = -1.99 m. What will the block s speed be when it reaches x = 0? New problem Same type of track as in the previous problem, this time with d = 4.73 m. The block starts at x = 0, and is given a push to the left with an initial speed of 7.57 m/s, so it starts sliding up the track to the left. At what value of x will the block reverse direction and start sliding back down? -3.72 m 3.72 m 2.92 m -2.92 m
Use conservation of energy to solve both parts of the following problem (initial kinetic energy + initial gravitational potential energy = final kinetic energy + final gravitational potential energy): A skydiver with a mass of 80.0 kg steps out of a hot-air balloon holding at an altitude of 1.00 km and opens their parachute at an altitude of 200. m. While they’re in free-fall, there is a total drag force of 50.0 N on them. Once the parachute has opened, there is a total drag force of 3.60 kN on them. (y = 0 at 200. m) (a) How fast is the skydiver going when they open their parachute? (b) How fast will they be going once they touch down?
Asap
A helicopter is dellvering food in an emergency situation, where it is difficult to land. The engineer is tasked with determining what heights the package could be dropped without breaking. She knows that if the package strikes the ground faster than the critical speed of 62.0mph, then the package will break. Neglect drag At what height would the package hit the ground with the critical speed (in given units? Could the package be safely dropped from a height of 30m? yes no
While at a water park, Hunter tries the water slide. The starting point is 13.0 m above the ground. He pushes off with an initial speed of 2.5 m/s. If the slide is frictionless, how fast will Hunter be traveling at the bottom?
The friction force that a horizontal surface exerts on a 66-kg object is 17 N. If the initial speed of the object is20 m/s, what distance will it slide before coming to a stop? Calculate to one decimal