Question 1.: A sample of 5.50 kilograms of water at 6.00°C is placed in the freezer. Assuming all energy removed from the freezer is removed from the water, how long does the 1/5 horsepower (HP) motor (1 HP = 746 Watts) have to run to cool all of the liquid to ice at 0.00°C? The freezer has a COP of 5.00. Your challenge: come up with a complete equation solved for the variable in question before you plug in any of the numerical values given above. In this way, you will be prepared to solve for any of the variables! Some questions to consider along the way ... (a.) What is the relationship between power, P (in watts) and work, W (in joules)? What is the variable you are eventually solving for? (b.) What is the relationship between the COP of a freezer/refrigerator, and work? (c.) How much energy as heat must be removed from the water to freeze it? What heat pump/refrigerator variable does this value correspond to? freezer run time = 154.2 S = 2.57 minutes Question 2.: Energy as heat is input into a steam turbine to convert 13.5 kg of liquid water at 25.0°C to water vapor at 100.0°C every hour. The efficiency of this heat engine is 22.2%: (2.A) What is the power output of the heat engine, in watts? P = (2.B) The temperature of the heat engine's boiler is 100.0°C, while the exhaust reservoir is maintained at 8.00°C. What is the difference between the theoretical maximum efficiency if the engine, and its actual efficiency? Please express your answer as a percentage. %

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 1.: A sample of 5.50 kilograms of water at 6.00°C is placed in the freezer. Assuming all energy removed from the freezer is removed from the water, how long does the 1/5 horsepower (HP) motor (1
HP = 746 Watts) have to run to cool all of the liquid to ice at 0.00°C? The freezer has a COP of 5.00.
Your challenge: come up with a complete equation solved for the variable in question before you plug in any of the numerical values given above. In this way, you will be prepared to solve for any of the variables!
Some questions to consider along the way ...
(a.) What is the relationship between power, P (in watts) and work, W (in joules)? What is the variable you are eventually solving for?
(b.) What is the relationship between the COP of a freezer/refrigerator, and work?
(c.) How much energy as heat must be removed from the water to freeze it? What heat pump/refrigerator variable does this value correspond to?
freezer run time = 154.2
5 = 2.57
minutes
Question 2.: Energy as heat is input into a steam turbine to convert 13.5 kg of liquid water at 25.0°C to water vapor at 100.0°C every hour. The efficiency of this heat engine is 22.2%.
(2.A) What is the power output of the heat engine, in watts?
P =
(2.B) The temperature of the heat engine's boiler is 100.0°C, while the exhaust reservoir is maintained at 8.00°C. What is the difference between the theoretical maximum efficiency if the engine, and its
actual efficiency? Please express your answer as a percentage.
%
Transcribed Image Text:Question 1.: A sample of 5.50 kilograms of water at 6.00°C is placed in the freezer. Assuming all energy removed from the freezer is removed from the water, how long does the 1/5 horsepower (HP) motor (1 HP = 746 Watts) have to run to cool all of the liquid to ice at 0.00°C? The freezer has a COP of 5.00. Your challenge: come up with a complete equation solved for the variable in question before you plug in any of the numerical values given above. In this way, you will be prepared to solve for any of the variables! Some questions to consider along the way ... (a.) What is the relationship between power, P (in watts) and work, W (in joules)? What is the variable you are eventually solving for? (b.) What is the relationship between the COP of a freezer/refrigerator, and work? (c.) How much energy as heat must be removed from the water to freeze it? What heat pump/refrigerator variable does this value correspond to? freezer run time = 154.2 5 = 2.57 minutes Question 2.: Energy as heat is input into a steam turbine to convert 13.5 kg of liquid water at 25.0°C to water vapor at 100.0°C every hour. The efficiency of this heat engine is 22.2%. (2.A) What is the power output of the heat engine, in watts? P = (2.B) The temperature of the heat engine's boiler is 100.0°C, while the exhaust reservoir is maintained at 8.00°C. What is the difference between the theoretical maximum efficiency if the engine, and its actual efficiency? Please express your answer as a percentage. %
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