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Solve p=31(0.65) 9= -2.57 graphically for q if p = 10. (give your answer accurate to at least 1 decimal place)

Solve p=31(0.65) 9= -2.57 graphically for q if p = 10. (give your answer accurate to at least 1 decimal place)

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem:** Solve \( p = 31(0.65)^q \) graphically for \( q \) if \( p = 10 \). \( q = -2.57 \) *(Give your answer accurate to at least 1 decimal place)* **Explanation:** This problem involves solving an exponential equation graphically. The goal is to find the value of \( q \) when \( p \) is given as 10. The expression involves an initial value (31) and a base (0.65) raised to the power \( q \). To solve this graphically, you would typically plot: 1. The function \( y = 31(0.65)^q \). 2. A horizontal line representing \( y = 10 \). The solution for \( q \) is the x-coordinate of the point where these two graphs intersect. In this case, the solution is \( q = -2.57 \), which indicates the x-value where the function \( 31(0.65)^q \) equals 10.
Transcribed Image Text:**Problem:** Solve \( p = 31(0.65)^q \) graphically for \( q \) if \( p = 10 \). \( q = -2.57 \) *(Give your answer accurate to at least 1 decimal place)* **Explanation:** This problem involves solving an exponential equation graphically. The goal is to find the value of \( q \) when \( p \) is given as 10. The expression involves an initial value (31) and a base (0.65) raised to the power \( q \). To solve this graphically, you would typically plot: 1. The function \( y = 31(0.65)^q \). 2. A horizontal line representing \( y = 10 \). The solution for \( q \) is the x-coordinate of the point where these two graphs intersect. In this case, the solution is \( q = -2.57 \), which indicates the x-value where the function \( 31(0.65)^q \) equals 10.
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p = 31(0.65)q

p = 10

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