**Question #1: Propose an answer for the following spectra and justify your answer.**1. The graph shown is a mass spectrum. It displays the relative abundance of ions as a function of their mass-to-charge (m/z) ratio. - The y-axis represents the % abundance, which indicates the relative quantity of each ion detected.- The x-axis represents the m/z ratio, commonly used in mass spectrometry for identifying compounds.Key observations from the spectrum:- Peaks are observed at m/z values 50, 51, 77, and a double peak at 156 and 158.- The peak at m/z 77 has the highest relative abundance, suggesting it is a base peak.- The peaks at m/z 156 and 158 might indicate the presence of a molecular ion with a natural isotopic distribution.The assignment involves proposing a potential structure or compound represented by this spectrum, taking into account the m/z ratios and the pattern of peaks.

Mass spectrometry is a very useful technique to find out the structure of an unknown organic compound by the mass of the possible fragments in the compound. The highest peak is called the base peak in mass spectra. The molecular ion peak shows the molecular mass of the compound. The molecular ion peak is 156. So the molecular mass of the compound is 156. There is one (M+2) peak at 158 with the same intensity. The base peak is at 77. So 156 - 77 = 79. There should be one bromine atom. Also, bromine has two isotopes (79Br and 81Br). The abundance of both isotopes is nearly 50%. Hence M+2 peak has the same intensity as that of the molecular ion peak. 77 - 51 = 26, so C2H2 group is released. Hence the compound is bromobenzene. The compound is bromobenzene.

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QUESTION #1 PROPOSE ANSWER FOR THE FOLLOWING SPECTRA? AND JUSTIFY YOUR ANSWER 1- %abundance 90 70 60 50 40 30 20 10 58 1558 Julb. 符時以33322383830日030年民法院民员 m/z ratio

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