Question 1 Consider the equation x² − 2x³ + 2x² − 3x + 1 = 0. 24 (a) Is there a solution on [0, 1]? (b) In order to find the solution on [0, 1] using Bisection Method, estimate how

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Question 1 Consider the equation r4 - 2x³ + 2x² − 3x + 1 = 0.
(a) Is there a solution on [0, 1]?
(b) In order to find the solution on [0, 1] using Bisection Method, estimate how
many iterations will be needed.
Transcribed Image Text:Question 1 Consider the equation r4 - 2x³ + 2x² − 3x + 1 = 0. (a) Is there a solution on [0, 1]? (b) In order to find the solution on [0, 1] using Bisection Method, estimate how many iterations will be needed.
Expert Solution
Step 1: Existence of the solution:

L e t space f left parenthesis x right parenthesis equals x to the power of 4 minus 2 x cubed plus 2 x squared minus 3 x plus 1 equals 0
N o w comma space f left parenthesis 0 right parenthesis equals 1 space a n d space f left parenthesis 1 right parenthesis equals negative 1.
A s comma space f left parenthesis 0 right parenthesis. f left parenthesis 1 right parenthesis less than 0 comma space there exists x element of left parenthesis 0 comma 1 right parenthesis space s u c h space t h a t space f left parenthesis x right parenthesis equals 0.
H e n c e comma space t h e r e space i s space a space s o l u t i o n space o n space left square bracket 0 comma 1 right square bracket.

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