Question 1: Consider the bubble sort algorithm: BubbleSort(A[1...n]) false; k = n ; sw = repeat false ; for i = 1 tok – 1 do if A[i] > A[i + 1] then Swap A[i] and A[i + 1] ; SW = sw = true ; end end k = k – 1; until sw = false; Algorithm 1: Bubblesort In each iteration of the outermost loop, we scan through the array, if there is a consecutive pair of entries that is in the wrong order, we swap them. We stop when there is no swap, i.e., the array is sorted. Part a) After the first iteration of the outermost loop, why must the largest element ends up being in A[n]? After the second iteration of the outermost loop, why must the second largest element ends up being in A[n – 1]. What is the generalized observation after the ith iteration of the outermost loop? Then conclude that after the nth iteration of the outermost loop, A is sorted. Part b) What is the running time of the algorithm Please justify your answer
Question 1: Consider the bubble sort algorithm: BubbleSort(A[1...n]) false; k = n ; sw = repeat false ; for i = 1 tok – 1 do if A[i] > A[i + 1] then Swap A[i] and A[i + 1] ; SW = sw = true ; end end k = k – 1; until sw = false; Algorithm 1: Bubblesort In each iteration of the outermost loop, we scan through the array, if there is a consecutive pair of entries that is in the wrong order, we swap them. We stop when there is no swap, i.e., the array is sorted. Part a) After the first iteration of the outermost loop, why must the largest element ends up being in A[n]? After the second iteration of the outermost loop, why must the second largest element ends up being in A[n – 1]. What is the generalized observation after the ith iteration of the outermost loop? Then conclude that after the nth iteration of the outermost loop, A is sorted. Part b) What is the running time of the algorithm Please justify your answer
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![Question 1: Consider the bubble sort algorithm: BubbleSort(A[1...n])
- false;
k = n ;
repeat
SW =
false ;
for i = 1 tok – 1 do
if A[i] > A[i + 1] then
Swap A[i] and A[i + 1] ;
SW =
sw =
true ;
end
end
k = k – 1;
until sw =
false;
Algorithm 1: Bubblesort
In each iteration of the outermost loop, we scan through the array, if there is
a consecutive pair of entries that is in the wrong order, we swap them. We stop
when there is no swap, i.e., the array is sorted.
Part a) After the first iteration of the outermost loop, why must the largest
element ends up being in A[n]? After the second iteration of the outermost loop,
why must the second largest element ends up being in A[n – 1]. What is the
generalized observation after the ith iteration of the outermost loop? Then conclude
that after the nth iteration of the outermost loop, A is sorted.
Part b) What is the running time of the algorithm. Please justify your answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe51b7cfc-e50d-4c51-aa17-d485ca4ccb1a%2F7a32b670-555a-4568-87ff-84c0fe53c20b%2F7mkzmvl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 1: Consider the bubble sort algorithm: BubbleSort(A[1...n])
- false;
k = n ;
repeat
SW =
false ;
for i = 1 tok – 1 do
if A[i] > A[i + 1] then
Swap A[i] and A[i + 1] ;
SW =
sw =
true ;
end
end
k = k – 1;
until sw =
false;
Algorithm 1: Bubblesort
In each iteration of the outermost loop, we scan through the array, if there is
a consecutive pair of entries that is in the wrong order, we swap them. We stop
when there is no swap, i.e., the array is sorted.
Part a) After the first iteration of the outermost loop, why must the largest
element ends up being in A[n]? After the second iteration of the outermost loop,
why must the second largest element ends up being in A[n – 1]. What is the
generalized observation after the ith iteration of the outermost loop? Then conclude
that after the nth iteration of the outermost loop, A is sorted.
Part b) What is the running time of the algorithm. Please justify your answer.
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