QUESTION 1 Consider a two-degrees-of-freedom system shown below. k₁ www Use m1= 3 kg m2 = 2 kg k1= 125 N/m k2 = 160 N/m m k3 123 N/m k₂ -00000 F1 - 334 cos(1.91) N F2=0. F₁ M₂ What is the amplitude of vibration of mass 1 oscillating at the input frequency? (This is just another way of asking for the amplitude of the particular solution). The answer must be positive. Use scientific notation with 3 significant figures. Omit units. k mome F₁
QUESTION 1 Consider a two-degrees-of-freedom system shown below. k₁ www Use m1= 3 kg m2 = 2 kg k1= 125 N/m k2 = 160 N/m m k3 123 N/m k₂ -00000 F1 - 334 cos(1.91) N F2=0. F₁ M₂ What is the amplitude of vibration of mass 1 oscillating at the input frequency? (This is just another way of asking for the amplitude of the particular solution). The answer must be positive. Use scientific notation with 3 significant figures. Omit units. k mome F₁
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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AMPLITUDE OF VIBRATION ( NO GPT)

Transcribed Image Text:QUESTION 1
Consider a two-degrees-of-freedom system shown below.
+0+0+
m₁
m₂
k₁
Use
What is the amplitude of vibration of mass 1 oscillating at the input frequency? (This is just another way of asking for the amplitude of the particular solution). The answer must be positive. Use scientific notation with 3 significant figures.
Omit units.
m1 = 3 kg
m2 = 2 kg
k1 = 125 N/m
0000
k2= 160 N/m
k3= 123 N/m
F1 = 334 cos(1.9t) N
F2 = 0.
F₂
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