Question 1: Assume that you are using a double convex lens with focal length f = 4.22 and you place an object of height ho = 1 unit at the position x = -10 which corresponds to an object distance of do= |-10| = 10 units. Calculate the image distance di, the magnification, describe the type of image formed and state whether it is upright or inverted. (Show your calculations below)

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Chapter1: Units, Trigonometry. And Vectors
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Lens Equation: Lab Activity
The relationship between the object distance do, image distance di and the focal length f can be modeled by
the thin lens equation
1
1
d,* d
A thin lens is a lens where the width of the lens is a lot smaller than the diameter of the lens.
Double convex lens: Assume that the objects distance do is positive if it's to the left of the lens, the image
distance di is positive if it's to the right of the lens, the focal point is positive if its on the other side of the lens
as the object.
Double concave lens: Assume that the objects distance d, is positive if it's to the left of the lens, the image
distance di is negative if it's on the same side of the lens, and the focal point is negative if it's on the same side
as the object.
Focal length is positive if working with a double convex lens and negative is working with a double concave
lens.
The lens magnification can be described using the formula m =: where h, is the objects height, and h,
ho
do
is the images height.
Simulation link: http://ophysics.com/l12.html
In this activity you will use the thins lens equation to find the objects distance analytically and then verify it
using the provided simulation.
Question 1: Assume that you are using a double convex lens with focal length f = 4.22 and you place an object
of height ho = 1 unit at the position x = -10 which corresponds to an object distance of do= |-10| = 10 units.
Calculate the image distance d, the magnification, describe the type of image formed and state whether it is
upright or inverted. (Show your calculations below)
Transcribed Image Text:Lens Equation: Lab Activity The relationship between the object distance do, image distance di and the focal length f can be modeled by the thin lens equation 1 1 d,* d A thin lens is a lens where the width of the lens is a lot smaller than the diameter of the lens. Double convex lens: Assume that the objects distance do is positive if it's to the left of the lens, the image distance di is positive if it's to the right of the lens, the focal point is positive if its on the other side of the lens as the object. Double concave lens: Assume that the objects distance d, is positive if it's to the left of the lens, the image distance di is negative if it's on the same side of the lens, and the focal point is negative if it's on the same side as the object. Focal length is positive if working with a double convex lens and negative is working with a double concave lens. The lens magnification can be described using the formula m =: where h, is the objects height, and h, ho do is the images height. Simulation link: http://ophysics.com/l12.html In this activity you will use the thins lens equation to find the objects distance analytically and then verify it using the provided simulation. Question 1: Assume that you are using a double convex lens with focal length f = 4.22 and you place an object of height ho = 1 unit at the position x = -10 which corresponds to an object distance of do= |-10| = 10 units. Calculate the image distance d, the magnification, describe the type of image formed and state whether it is upright or inverted. (Show your calculations below)
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