Aperture stop: Consider an optical system made up of two convex thin lenses (L1 and L2) and a diaphragm D located in between, as shown in the figure below. OP is the object. Focal length of Li and L2 are 2a and a, respectively. Distances between the optical elements have the following relationship: s = 1Oa, 1 = 4a, and d = 6a, respectively Dimensions of L1, L2, and D are ri = r2= 3r and r3 = r. Locate the position and size of aperture stop (AS), entrance pupil (E„P), and exit pupil (E,P) for the system. D. object
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- Shown in the figure below is a system containing two lenses and an object. The focal lengths of the two lenses are f1 = -19 cm and f2 = 9.5 cm. The two lengths indicated in the figure are L1 = 28.5 cm and L2 = 15.2 cm. Determine all the following about the image from the first lens only:Object distance for the first lens, d01. cmImage distance for the first lens, di1. cmMagnification of the first lens, m1. The second lens uses the image from the first lens as its object. Determine all the following about the image from the second lens:Object distance for the second lens, d01. cmImage distance for the second lens, di1. cmMagnification of the second lens, m1. Determine the magnification of the whole system, mtot. Select the correct attributes of the final image of the system: virtual real enlarged shrunk upside down right side upPlease asap1 + So 1 Thin Lens Equation: Mr = Si Yo So Principle Ray: the ray from object to lens that is parallel to the principle (optical) axis will refract in a path that intersects the image focal point. Focal Ray: the ray from the object whose path is directed towards the object focal point will refract in a path parallel the principle (optical) axis. Central Ray: the ray from the object whose path is directed towards the center of the lens (intersection with the principle axis) will emerge from the lens undeflected. Conventions: Quantity Sign Positive (+) Negative (-) Object distance So Real object Virtual object Image distance Si Real image Virtual image Focal length f Converging lens Diverging Lens (opposite side of o,i) Object height Yo Erect object Inverted object Image height Yi Erect image Inverted image Magnification (transverse) MT Erect image Inverted image For the following lens configurations, carefully generate a ray trace diagram to locate the image graphically. Use the thin…
- A converging lens has a focal length of 4.0 cm A 1.5 cm object is placed 6.0 cm to the left of the lens (as shown in the diagram below) Part A The distance of the image will be ανα ΑΣφ d; = cm Submit Request Answer Part B The height of the image will be Πνη ΑΣφ ? h4 = cm Submit Request Answer Part C The image is and O real, upright O real, inverted O virtual, inverted O virtual, uprightPhysics Optics: For an infinity optical system, explain why the magnification is determined by the ratio of the focal tube length over the focal objective length. Include a diagram showing the focal tube length and the focal objective.You unconsciously estimate the distance to an object from the angle it subtends in your field of view. This angle 0 in radians is related to the linear height of the object h and to the distance d by 0= h/d. Assume that you are driving a car and that another car, 1.50 m high, is 22.0 m behind you. KTO & $3 m (d) What angle does the image subtend at your eyes? rad (e) Based on its angular size, how far away does the following car appear to be? m 0 1900 Per Works Inc OBJECTS IN MIRROR ARE CLOSER THAN THEY APPEAR vestest by Creators Syndicate The Far Side by Gary Larson 1985 FarWorks, Inc. All Rights Reserved. Used with permission. (a) Suppose your car has a flat passenger-side rearview mirror, 1.55 m from your eyes. How far from your eyes is the image of the car following you? m (b) What angle does the image subtend in your field of view? rad (c) Suppose instead your car has a convex rearview mirror (see figures) with a radius of curvature of magnitude 1.70 m. How far from your eyes is…
- (Figure 1) shows an object and its image formed by a thin lens. Assume that L = 16.2 cm and y = 3.45 mm. Figure Image Object 6.00 cm L 1 of 1 Optic axis Lens Part A What is the focal length of the lens? Express your answer in centimeters. - ΑΣΦ f = Submit Part B What type of lens is it? Submit Request Answer converging diverging Part C II Request Answer What is the height of the image? Express your answer in millimeters. Π ΑΣΦ = ? ? cm mmFamous jeweler Gabi Tolkowsky is looking at a 3.0-cm-tall perfect oval-shaped diamond through a thin lens. The diamond is 20.0 cm behind the lens, and the distance between its upright image and the lens is 40.0 cm. What is the focal length of the lens? Is it converging or diverging? How tall is the image? PLEASE PLEASE draw a ray diagram and define variablesPlease help me to prove this equation in this picture below
- Help.Spherical refracting surfaces. An object O stands on the central axis of a spherical refracting surface. For this situation (see the table below, all distances are in centimeters), nį is the index of refraction where the object is located, n2 is the index of refraction on the other side of the refracting surface. Find (a) the image distance i, and determine whether the image is (b) real or virtual and (c) on the same side of the surface as object O or on the opposite side. (a) (b) (c) n1 n2 p ri R/V Side 1.5 1.3 +70 +56 (a) Number i Units (b) (c) > >Case 2: Object distance d0 >R. The figure below shows an arrow-shaped object, located in front of a convex lens at a distance d0 greater than the radius of curvature R. Draw the following rays in the figure: i) Ray parallel to the optical axis; ii) Focal ray; iii) Central ray, iv) Draw the image of the arrow, v) Indicate in the same figure, from where to where di (image-lens distance) is. Use the figure, Do not substitute it with any other figure. Don't forget to put the direction on each ray, both the incident rays and the transmitted rays. Label each ray. Image characteristics for Case 2: Object distance d0 > R. Choose the ones that apply: a) Virtual b) Real c) Inverted d) Increased e) No image is formed f) Equal size g) Reduced h) Erect