Question 1-a, Numerical: The next figure shows an 80.0 kg cat burglar at static equilibrium. Assume the angle 8 of the inclined cable is 48.0°, find the tension in the inclined cable (T₁) measured in N. T, T
Question 1-a, Numerical: The next figure shows an 80.0 kg cat burglar at static equilibrium. Assume the angle 8 of the inclined cable is 48.0°, find the tension in the inclined cable (T₁) measured in N. T, T
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:**Question 1-a, Numerical:**
The next figure shows an 80.0 kg cat burglar at static equilibrium. Assume the angle θ of the inclined cable is 48.0°, find the tension in the inclined cable (T1) measured in N.
**Diagram Explanation:**
The figure depicts a scenario where an individual (referred to as a cat burglar) is hanging from a system of cables. The tension in the cables helps to keep the person in static equilibrium. The following elements are included in the diagram:
- An inclined cable labeled as \( T_1 \) making an angle θ (48.0°) with the horizontal.
- A vertical cable labeled as \( T_2 \) that connects the person directly to the support point.
- The person hanging represents a mass of 80.0 kg.
The task is to calculate the tension in the inclined cable \( T_1 \), given the mass of the person and the angle θ.
(Note: The actual values and calculations related to this question are to be determined through the application of physics concepts addressing forces in static equilibrium.)

Transcribed Image Text:### Question 1-b, Numerical:
The next figure shows an 80.0 kg cat burglar at static equilibrium. Assume the angle θ of the inclined cable is 48.0°, find the tension in the horizontal cable (T₂) measured in N.
#### Explanation of the Diagram:
- The diagram depicts a person hanging with the help of two cables.
- There is a horizontal cable labeled \( T_2 \).
- An inclined cable is labeled \( T_1 \) and makes an angle \( \theta \) with the horizontal direction.
- The angle \( \theta \) between the inclined cable and the horizontal direction is given as 48.0°.
- The person is hanging in static equilibrium, meaning the sum of the forces in every direction is zero.
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