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QUESTION 1 A horizontal well with a measured depth of 10,000 ft. can be approximated as being vertical to 2,000 ft, then a 5,000-ft segment inclined at 60 deg, and a horizontal 3,000- It section. Given: 2,000 Hole diameter (constant) = 8.5 in Drillstring OD = 5 in Mud weight= 10 ppg Flow rate = 400 gpm 5,000 f 60 deg Calculate:

QUESTION 1 A horizontal well with a measured depth of 10,000 ft. can be approximated as being vertical to 2,000 ft, then a 5,000-ft segment inclined at 60 deg, and a horizontal 3,000- It section. Given: 2,000 Hole diameter (constant) = 8.5 in Drillstring OD = 5 in Mud weight= 10 ppg Flow rate = 400 gpm 5,000 f 60 deg Calculate:

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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QUESTION 1 A horizontal well with a measured depth of 10,000 ft. can be approximated as being vertical to 2,000 ft, then a 5,000-ft segment inclined at 60 deg, and a horizontal 3,000- It section. Given: 2.000 Hole diameter (constant)= 8.5 in Drillstring OD = 5 in Mud weight = 10 ppg Flow rate = 400 gpm 5,000 ft 60 deg Calculate: 3,000 ft a) The hydrostatic pressure at bottom (10,000 ft) psi b) The time necessary to bring the cuttings through the annulus, from the bottom to the surface. min
Transcribed Image Text:QUESTION 1 A horizontal well with a measured depth of 10,000 ft. can be approximated as being vertical to 2,000 ft, then a 5,000-ft segment inclined at 60 deg, and a horizontal 3,000- It section. Given: 2.000 Hole diameter (constant)= 8.5 in Drillstring OD = 5 in Mud weight = 10 ppg Flow rate = 400 gpm 5,000 ft 60 deg Calculate: 3,000 ft a) The hydrostatic pressure at bottom (10,000 ft) psi b) The time necessary to bring the cuttings through the annulus, from the bottom to the surface. min
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