QI. An engineer or scientist is measuring the output of a pin of an IC. It turns out that the outputs are cither 0 or 1 (onc can think of 0 as 0 volts and 1 as the 5 volts). The engineer /scientist is informed that the output is governed by a probability mass function. Therefore, the output can be treated as a random variable and since the outcomes belong to the set {0,1}, it is a discrete random variable (we denote it by X). It turns out that the probability of getting X=1 is 0.3, i.e., p(x=1)=P, where P=0.3. The probability mass function is given as follows x = 0 x = 1' where P= 0.3. This pmf can also be represented as (1- P, f(x) = {p f(x)=P*(1-P)-. a) Find the mean (expected value) of X. This means that what do we get in the output, on the average. b) Find the variance of the random variable X c) Now the engineer/scientist, starts measuring the output. He/she repeats the process 20 times. The outcomes are as follows. X = [1 0 0 0 0 0 o 0 1 0 11 110 0 0 0 1 o] c-1) Plot the histogram of data
QI. An engineer or scientist is measuring the output of a pin of an IC. It turns out that the outputs are cither 0 or 1 (onc can think of 0 as 0 volts and 1 as the 5 volts). The engineer /scientist is informed that the output is governed by a probability mass function. Therefore, the output can be treated as a random variable and since the outcomes belong to the set {0,1}, it is a discrete random variable (we denote it by X). It turns out that the probability of getting X=1 is 0.3, i.e., p(x=1)=P, where P=0.3. The probability mass function is given as follows x = 0 x = 1' where P= 0.3. This pmf can also be represented as (1- P, f(x) = {p f(x)=P*(1-P)-. a) Find the mean (expected value) of X. This means that what do we get in the output, on the average. b) Find the variance of the random variable X c) Now the engineer/scientist, starts measuring the output. He/she repeats the process 20 times. The outcomes are as follows. X = [1 0 0 0 0 0 o 0 1 0 11 110 0 0 0 1 o] c-1) Plot the histogram of data
A First Course in Probability (10th Edition)
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Binomial Distribution
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![Q1. An engineer or scientist is measuring the output of a pin of an IC. It turns out that the outputs are
either 0 or 1 (one can think of 0 as 0 volts and 1 as the 5 volts). The engineer /scientist is informed that
the output is governed by a probability mass function. Therefore, the output can be treated as a random
variable and since the outcomes belong to the set {0,1}, it is a discrete random variable (we denote it by
X). It turns out that the probability of getting X=1 is 0.3, i.e., p(x=1)=P, where P=0.3. The probability
mass function is given as follows
x = 0
x = 1'
(1- P,
f(x) = {P,
where P= 0.3. This pmf can also be represented as
%3D
f(x)=P*(1-P)--×.
a) Find the mean (expected value) of X. This means that what do we get in the output, on the
average.
b) Find the variance of the random variable X
c) Now the engineer/scientist, starts measuring the output. He/she repeats the process 20 times. The
outcomes are as follows.
X = [1 0 0 0 0 o o 0 1 0 11 1 1 0 0 0 0 1 o]
c-1) Plot the histogram of data
c-2) Normalize the histogram and plot it.
c-3) Find the mean and variance of the collected samples. Find the probability of p(X=1) from the
collected measurements (is this the same as the actual probability P?). Compare the results with the actual
mean and variances. Are they different? Explain what you learned from this problem.
c-4) Represent the data with the approximated pmf (look at the actual pmf and instead of P use the
probability of p(X=1) you found from the data). Plot the approximated and the actual pmfs.
Note: The random variable in this problem is called Bernoulli. Meaning that X is governed by a Bernoulli
distribution. In most real world problems, we do not now the actual distribution of our data. However, we
can model our data via a famous distribution (such as Bernoulli) based on the samples we get (look at
what you did in part c).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F199d58c4-213a-4e42-b645-d01318acf93a%2F84b6bb64-0cd1-4f2a-a793-05b00eb80670%2F706am5o_processed.png&w=3840&q=75)
Transcribed Image Text:Q1. An engineer or scientist is measuring the output of a pin of an IC. It turns out that the outputs are
either 0 or 1 (one can think of 0 as 0 volts and 1 as the 5 volts). The engineer /scientist is informed that
the output is governed by a probability mass function. Therefore, the output can be treated as a random
variable and since the outcomes belong to the set {0,1}, it is a discrete random variable (we denote it by
X). It turns out that the probability of getting X=1 is 0.3, i.e., p(x=1)=P, where P=0.3. The probability
mass function is given as follows
x = 0
x = 1'
(1- P,
f(x) = {P,
where P= 0.3. This pmf can also be represented as
%3D
f(x)=P*(1-P)--×.
a) Find the mean (expected value) of X. This means that what do we get in the output, on the
average.
b) Find the variance of the random variable X
c) Now the engineer/scientist, starts measuring the output. He/she repeats the process 20 times. The
outcomes are as follows.
X = [1 0 0 0 0 o o 0 1 0 11 1 1 0 0 0 0 1 o]
c-1) Plot the histogram of data
c-2) Normalize the histogram and plot it.
c-3) Find the mean and variance of the collected samples. Find the probability of p(X=1) from the
collected measurements (is this the same as the actual probability P?). Compare the results with the actual
mean and variances. Are they different? Explain what you learned from this problem.
c-4) Represent the data with the approximated pmf (look at the actual pmf and instead of P use the
probability of p(X=1) you found from the data). Plot the approximated and the actual pmfs.
Note: The random variable in this problem is called Bernoulli. Meaning that X is governed by a Bernoulli
distribution. In most real world problems, we do not now the actual distribution of our data. However, we
can model our data via a famous distribution (such as Bernoulli) based on the samples we get (look at
what you did in part c).
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