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QI. A conical shaft is turning with an angular velocity of w-200 rad/sec in a rectangular bearing which is fixed. The gap between shaft and bearing is filled with a kind of oil (Newtonian fluid) having a dynamic viscosity of u-0.5 N.s/m?. a) Calculate the torque produced by the side gaps as the inner conical shaft rotates. b) Calculate the additional viscous torque produced by the flat bottom of the conical shaft. w=200 rad/s h=5 cm h=0.5 cm h=0.5 cm

QI. A conical shaft is turning with an angular velocity of w-200 rad/sec in a rectangular bearing which is fixed. The gap between shaft and bearing is filled with a kind of oil (Newtonian fluid) having a dynamic viscosity of u-0.5 N.s/m?. a) Calculate the torque produced by the side gaps as the inner conical shaft rotates. b) Calculate the additional viscous torque produced by the flat bottom of the conical shaft. w=200 rad/s h=5 cm h=0.5 cm h=0.5 cm

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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QI. A conical shaft is turning with an angular velocity of w-200 rad/sec in a rectangular bearing which is fixed. The gap between shaft and bearing is filled with a kind of oil (Newtonian fluid) having a dynamic viscosity of u-0.5 N.s/m². a) Calculate the torque produced by the side gaps as the inner conical shaft rotates. b) Calculate the additional viscous torque produced by the flat bottom of the conical shaft. w=200 rad/s 309 h=5 cm h=0.5 cm h=0.5 cm
Transcribed Image Text:QI. A conical shaft is turning with an angular velocity of w-200 rad/sec in a rectangular bearing which is fixed. The gap between shaft and bearing is filled with a kind of oil (Newtonian fluid) having a dynamic viscosity of u-0.5 N.s/m². a) Calculate the torque produced by the side gaps as the inner conical shaft rotates. b) Calculate the additional viscous torque produced by the flat bottom of the conical shaft. w=200 rad/s 309 h=5 cm h=0.5 cm h=0.5 cm
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