Qi // Force (FD) proportional to pipe diameter (D); speed (V); fluid density (p); and fluid viscosity (u). How we can find an expression for force (FD)? (Using Raleigh's Method) Q2 // choose the correct answer: 1- The unit of dynamic viscosity of a fluid is--- m2 d) kg.s2 m2 Pa.s b) Ns m2 2- With increase of temperature, viscosity of a fluid--- a) Does not change b) Always increase c) Always decrease d) Increase, if the fluid is a gas and decrease, if it is a liquid.

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Qi // Force (FD) proportional to pipe diameter (D); speed (V); fluid
density (p); and fluid viscosity (u). How we can find an expression for
force (Fp)? (Using Raleigh's Method)
Q2 // choose the correct answer:
1- The unit of dynamic viscosity of a fluid is-----
m2
N.s
b)
m2
kg.s?
Pa.s
d)
m2
m2
2- With increase of temperature, viscosity of a fluid----
a) Does not change
b) Always increase
c) Always decrease
d) Increase, if the fluid is a gas and decrease, if it is a liquid.
3- Shear stress in the Newtonian fluid is proportional to-
a) pressure
b) strain
c) strain rate
d) the inverse of viscosity
4- specific weight of water at 4°C and 1 atm. Pressure is -
a)1000
m3
N
b)1001
m3
c)9810
m3
Q3 // Determine the gage pressure at the
center of the pipe (at point A) show in figure
1, with hi-40 cm and hz= 5cm. given
specific weight of mercury= 133000
- Pipe (section view)
N
m3
Water
specific weight of water= 9810 "
m3
Figure 1
Mercury
---Good Luck---
Transcribed Image Text:Qi // Force (FD) proportional to pipe diameter (D); speed (V); fluid density (p); and fluid viscosity (u). How we can find an expression for force (Fp)? (Using Raleigh's Method) Q2 // choose the correct answer: 1- The unit of dynamic viscosity of a fluid is----- m2 N.s b) m2 kg.s? Pa.s d) m2 m2 2- With increase of temperature, viscosity of a fluid---- a) Does not change b) Always increase c) Always decrease d) Increase, if the fluid is a gas and decrease, if it is a liquid. 3- Shear stress in the Newtonian fluid is proportional to- a) pressure b) strain c) strain rate d) the inverse of viscosity 4- specific weight of water at 4°C and 1 atm. Pressure is - a)1000 m3 N b)1001 m3 c)9810 m3 Q3 // Determine the gage pressure at the center of the pipe (at point A) show in figure 1, with hi-40 cm and hz= 5cm. given specific weight of mercury= 133000 - Pipe (section view) N m3 Water specific weight of water= 9810 " m3 Figure 1 Mercury ---Good Luck---
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