QI/ Determine the velocity of a plate which was lifted upward, if the force required for lifting it is 272.246 N and its weight is 90 N. This metal plate which its dimensions are 1.25 m x 1.25 m x 6 mm thick is placed midway in the 24 mm gap between the two vertical plane surfaces as shown in the Fig. below. The gap is filled with an oil of specific gravity 0.85 and dynamic viscosity 3000 mN.s/m². Vertical Plane Oil 6 mm 24 mm Plate
QI/ Determine the velocity of a plate which was lifted upward, if the force required for lifting it is 272.246 N and its weight is 90 N. This metal plate which its dimensions are 1.25 m x 1.25 m x 6 mm thick is placed midway in the 24 mm gap between the two vertical plane surfaces as shown in the Fig. below. The gap is filled with an oil of specific gravity 0.85 and dynamic viscosity 3000 mN.s/m². Vertical Plane Oil 6 mm 24 mm Plate
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:QI/ Determine the velocity of a plate which was lifted upward, if the
force required for lifting it is 272.246 N and its weight is 90 N. This
metal plate which its dimensions are 1.25 m x 1.25 m × 6 mm thick is
placed midway in the 24 mm gap between the two vertical plane
surfaces as shown in the Fig. below. The gap is filled with an oil of
specific gravity 0.85 and dynamic viscosity 3000 mN.s/m².
Vertical
Plane
Oil
6 mm
-24 mm
Plate
Transcribed Image Text:DELTA N
Ay= 24-6
2.
%3D
Out side f plak tow-ll/
[vdouty
at walliszwa}
3 XU
= lo00 v
3
Asea=
1.95 AL25 215625m2
(fosce is yplied on bok side of plete).
-2X 1000V X 1.5625
3/25V
Net torce upwald
Net force downweld
272-246
90+
1D00W 3125u
182.246
3125 V =
Va 175 mls
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