Q9. In the circuit, Vs1 is 121 V, Vs2 is 130 V, R1 is 3 Ohm, R2 is 6 Ohm, R3 is 2 Ohm, R4 is 9 Ohm, R5 is 10 Ohm, R6 is 29 Ohm. Hint: When solving the circuit using nodal analysis, ground the node where Vs1(-), Vs2(+) and R2 are connected. (Q9.a) Find the current i1 in the direction of the arrow. (Unit: A) (Q9.b) Find the current i2 in the direction of the arrow. (Unit: A) (Q9.c) Find the current i3 in the direction of the arrow. (Unit: A) (Q9.d) Find the current i4 in the direction of the arrow. (Unit: A) (Q9.e) Find the current i5 in the direction of the arrow. (Unit: A) (Q9.f) Find the current i6 in the direction of the arrow. (Unit: A)

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
icon
Related questions
Question

Q9. In the circuit, Vs1 is 121 V, Vs2 is 130 V, R1 is 3 Ohm, R2 is 6 Ohm, R3 is 2 Ohm, R4 is 9 Ohm, R5 is 10 Ohm, R6 is 29 Ohm.
Hint: When solving the circuit using nodal analysis, ground the node where Vs1(-), Vs2(+) and R2 are connected.

(Q9.a) Find the current i1 in the direction of the arrow. (Unit: A)

(Q9.b) Find the current i2 in the direction of the arrow. (Unit: A)

(Q9.c) Find the current i3 in the direction of the arrow. (Unit: A)

(Q9.d) Find the current i4 in the direction of the arrow. (Unit: A)

(Q9.e) Find the current i5 in the direction of the arrow. (Unit: A)

(Q9.f) Find the current i6 in the direction of the arrow. (Unit: A)

This diagram represents an electrical circuit containing two voltage sources and six resistors. It is useful for understanding the distribution of current in a complex circuit.

**Components:**
1. **Voltage Sources:**
   - \( V_{S1} \): Positioned at the upper left of the circuit.
   - \( V_{S2} \): Located below \( V_{S1} \).

2. **Resistors:**
   - \( R_1 \): Connected in series with \( V_{S1} \).
   - \( R_2 \): Connected in series with \( V_{S2} \).
   - \( R_3 \): Connected in parallel with \( R_1 \) and \( R_2 \).
   - \( R_4, R_5 \): Arranged in series and linked in parallel to \( R_1 \), \( R_2 \), and \( R_3 \).
   - \( R_6 \): Connected in parallel to the combination of resistors above, completing the circuit.

**Current Directions:**
- \( i_1 \): Flows through \( R_1 \).
- \( i_2 \): Flows through \( R_2 \).
- \( i_3 \): Flows through \( R_3 \).
- \( i_4 \): Flows downward through \( R_4 \).
- \( i_5 \): Flows downward through \( R_5 \).
- \( i_6 \): Flows downward through \( R_6 \).

**Circuit Analysis:**
This circuit illustrates a typical example for applying Kirchhoff’s laws: 
- Kirchhoff’s Current Law (KCL) at nodes where current divides or combines.
- Kirchhoff’s Voltage Law (KVL) in loops to verify the voltage drop calculations.

By analyzing the given resistors and current directions, one can apply Ohm's Law (\( V = IR \)) and the aforementioned laws to calculate unknown voltages, currents, or resistances, fostering a deeper understanding of electrical circuits.
Transcribed Image Text:This diagram represents an electrical circuit containing two voltage sources and six resistors. It is useful for understanding the distribution of current in a complex circuit. **Components:** 1. **Voltage Sources:** - \( V_{S1} \): Positioned at the upper left of the circuit. - \( V_{S2} \): Located below \( V_{S1} \). 2. **Resistors:** - \( R_1 \): Connected in series with \( V_{S1} \). - \( R_2 \): Connected in series with \( V_{S2} \). - \( R_3 \): Connected in parallel with \( R_1 \) and \( R_2 \). - \( R_4, R_5 \): Arranged in series and linked in parallel to \( R_1 \), \( R_2 \), and \( R_3 \). - \( R_6 \): Connected in parallel to the combination of resistors above, completing the circuit. **Current Directions:** - \( i_1 \): Flows through \( R_1 \). - \( i_2 \): Flows through \( R_2 \). - \( i_3 \): Flows through \( R_3 \). - \( i_4 \): Flows downward through \( R_4 \). - \( i_5 \): Flows downward through \( R_5 \). - \( i_6 \): Flows downward through \( R_6 \). **Circuit Analysis:** This circuit illustrates a typical example for applying Kirchhoff’s laws: - Kirchhoff’s Current Law (KCL) at nodes where current divides or combines. - Kirchhoff’s Voltage Law (KVL) in loops to verify the voltage drop calculations. By analyzing the given resistors and current directions, one can apply Ohm's Law (\( V = IR \)) and the aforementioned laws to calculate unknown voltages, currents, or resistances, fostering a deeper understanding of electrical circuits.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Similar questions
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,