S1 (a) R2 V₁ = 10V. C1 I₁(t) L2 Given the circuit in figure 7 with values R-3000-1300, R-5000-7000 - -HL-05MV-30V You are NOT allowed to solve the circut with phasors, a calculations must be domain switch initially closed and circ rower the following questions steady state and is opened at Questions and the switch 5, is closed and for questions to the switch is opened ww R4 Given the below answers for a), b) and c) find the following parts below them please R1 S₁ I, (+) R3 elew L₂=0.5H. R₁ = 3000 ((1₁-1₂) R₂=100.02 I C₁= IUF I₂(t) b. capacitor voltage at t=0 seconds is v₂(0) = 10 volts c. current flowing through inductor at t=0 is ₁,(0) = 6.667 mA 14=1 H R₂ = 50022. www R4=70052
KVL and KCL
KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.
Sign Convention
Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.
Given circuit:
Asked to find the,
- redraw the circuit with and label all voltages and current
- capacitor voltage at t=0- seconds,
- current flowing through inductor at t=0-
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