Q8. Given that y₁ (x) = ex is a solution of xy" - (2x + 1)y + (x + 1)y=0, x>0 then a second linearly independent solution is y₂(x) = A) x³ ex B) x¹ ex C) xe* D) x5 ex E) x² ex
Q8. Given that y₁ (x) = ex is a solution of xy" - (2x + 1)y + (x + 1)y=0, x>0 then a second linearly independent solution is y₂(x) = A) x³ ex B) x¹ ex C) xe* D) x5 ex E) x² ex
Q8. Given that y₁ (x) = ex is a solution of xy" - (2x + 1)y + (x + 1)y=0, x>0 then a second linearly independent solution is y₂(x) = A) x³ ex B) x¹ ex C) xe* D) x5 ex E) x² ex
Transcribed Image Text:Q8. Given that y₁ (x) = e* is a solution of
xy" - (2x + 1)y + (x + 1) = 0,
then a second linearly independent solution is y₂(x) =
A) x³ ex
B) x¹ ex
C) xe*
D) x5 ex
E) x² ex
x>0
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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