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1. Consider the differential equation (which we saw on the wk 1 test) dy %3D У (у + 1)?(2 —у) dt Explain whether or not there can be a solution that satisfies both y(0) = 1 and y(5) = 4, and why or why not.

1. Consider the differential equation (which we saw on the wk 1 test) dy %3D У (у + 1)?(2 —у) dt Explain whether or not there can be a solution that satisfies both y(0) = 1 and y(5) = 4, and why or why not.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Differential equation

Please write your explanation and don't use the calculator.

Consider the differential equation (which we saw on the wk 1 test)
??
?? = ?(? + 1)2(2 − ?)
Explain whether or not there can be a solution that satisfies both ?(0) = 1 and ?(5) = 4, and why or 
why not.

 

1. Consider the differential equation (which we saw on the wk 1 test) dy = y(y + 1)²(2 – y) dt Explain whether or not there can be a solution that satisfies both y(0) = 1 and y(5) = 4, and why or why not.
Transcribed Image Text:1. Consider the differential equation (which we saw on the wk 1 test) dy = y(y + 1)²(2 – y) dt Explain whether or not there can be a solution that satisfies both y(0) = 1 and y(5) = 4, and why or why not.
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