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Q8. Consider the mechanical system shown below. The system is initially at rest, and the displacementsr and z are measured from the equilibrium position. At7= 0, a force f(1) is applied to the svstem ki 9. Then, the equation of motion at degree of freedom y (DoF-y) is: A. mỹ + b(ý - 2) + k2(y- z) + k;(y- x) + f(t) - kz 0 B. mỹ + b(ý- 2) + k2(y- z) + k, (y-x) - f(t) + kzz = 0 C. mỹ + b(ý - 2) + k2(y- z) + k,(y - x) + f(t) = 0 D. mỹ + bý - 2) + k2(y - z) + k,(y-x) = 0 E. mỹ – b(ý – 2) – k2(y- z) – k,(y- x) = 0 %3D

Q8. Consider the mechanical system shown below. The system is initially at rest, and the displacementsr and z are measured from the equilibrium position. At7= 0, a force f(1) is applied to the svstem ki 9. Then, the equation of motion at degree of freedom y (DoF-y) is: A. mỹ + b(ý - 2) + k2(y- z) + k;(y- x) + f(t) - kz 0 B. mỹ + b(ý- 2) + k2(y- z) + k, (y-x) - f(t) + kzz = 0 C. mỹ + b(ý - 2) + k2(y- z) + k,(y - x) + f(t) = 0 D. mỹ + bý - 2) + k2(y - z) + k,(y-x) = 0 E. mỹ – b(ý – 2) – k2(y- z) – k,(y- x) = 0 %3D

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Q8. Consider the mechanical system shown below. The system is initially at rest, and the displacements x, y, and z are measured from the equilibrium position. Atr= 0, a force f(t) is applied to the y k: ki f0). ks 9. Then, the equation of motion at degree of freedom y (DoF-y) is: A. mỹ + b(ý - 2) + k2(y - z) + k; (y - x) + f(t) - k3z = 0 B. my + b(y- 2) + K2CY - z) + k, (y –x) - f(t) + k3z = 0 C. mỹ + b(ý - 2) + k2(y- z) + k;(y - x) + f(t) = 0 D. mỹ + b(ý - ż) + k2(y- z) + k, (y - x) = 0 E. mỹ – b(ý - ż) – k2(y – z) – k,(y-x) = 0 %3D
Transcribed Image Text:Q8. Consider the mechanical system shown below. The system is initially at rest, and the displacements x, y, and z are measured from the equilibrium position. Atr= 0, a force f(t) is applied to the y k: ki f0). ks 9. Then, the equation of motion at degree of freedom y (DoF-y) is: A. mỹ + b(ý - 2) + k2(y - z) + k; (y - x) + f(t) - k3z = 0 B. my + b(y- 2) + K2CY - z) + k, (y –x) - f(t) + k3z = 0 C. mỹ + b(ý - 2) + k2(y- z) + k;(y - x) + f(t) = 0 D. mỹ + b(ý - ż) + k2(y- z) + k, (y - x) = 0 E. mỹ – b(ý - ż) – k2(y – z) – k,(y-x) = 0 %3D
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