Q8: What will be the worst case complexities of the following codes: CODE 1: int FindMaxElement(int[] array) ( int max int.MinValue; for (int i= 1; i < array.Length; i++) ( if (array[1] > max) ( } return max; } CODE 2: long Sum3 (int n) ( long sum= 0; for (int a 1; a < n; a++) { max = array[i]; for (int b 1; b < n; b++) { } return sum;) for (int c 1; c < n; c++) ( suma b c; }
Q8: What will be the worst case complexities of the following codes: CODE 1: int FindMaxElement(int[] array) ( int max int.MinValue; for (int i= 1; i < array.Length; i++) ( if (array[1] > max) ( } return max; } CODE 2: long Sum3 (int n) ( long sum= 0; for (int a 1; a < n; a++) { max = array[i]; for (int b 1; b < n; b++) { } return sum;) for (int c 1; c < n; c++) ( suma b c; }
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![Q8: What will be the worst case complexities of the following codes:
CODE 1:
int FindMaxElement(int[] array)
{
}
int max= int.MinValue;
for (int i = 1; i < array.Length; i++)
{
if (array[i]> max)
{
}
}
return max;
CODE 2:
long Sum3 (int n)
{
max = array[i];
long sum = 0;
for (int a 1; a< n; a++)
{
for (int b= 1; b < n; b++)
{
}
}
return sum; }
for (int c 1; c < n; c++)
{
}
sum +
a b c;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8d223716-e0cf-4821-aa09-3d7caabe3e00%2F5a959314-9e67-44ce-b20c-df31c0e71ee9%2F8ruzguo_processed.png&w=3840&q=75)
Transcribed Image Text:Q8: What will be the worst case complexities of the following codes:
CODE 1:
int FindMaxElement(int[] array)
{
}
int max= int.MinValue;
for (int i = 1; i < array.Length; i++)
{
if (array[i]> max)
{
}
}
return max;
CODE 2:
long Sum3 (int n)
{
max = array[i];
long sum = 0;
for (int a 1; a< n; a++)
{
for (int b= 1; b < n; b++)
{
}
}
return sum; }
for (int c 1; c < n; c++)
{
}
sum +
a b c;
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