(Q75) The decomposition of gaseous nitric acid into its element is a nonspontaneous process with a value for AG°rxn of +73.5 kJ/mol for the process: HNO3(g) --> 1/2 H2 (g) + 1/2 N2 (g) + 3/2 O2 (g). What is the value of AGrxn if the reaction takes place at 727°C and the partial pressures of the gases are: PHNO3 = 0.882 atm, PH2 = 0.102 atm, PN2 = 0.161 atm, and Po2 = 0.00318 atm. (Recall that raising a number to the power of one-half is the same as taking its square root).
(Q75) The decomposition of gaseous nitric acid into its element is a nonspontaneous process with a value for AG°rxn of +73.5 kJ/mol for the process: HNO3(g) --> 1/2 H2 (g) + 1/2 N2 (g) + 3/2 O2 (g). What is the value of AGrxn if the reaction takes place at 727°C and the partial pressures of the gases are: PHNO3 = 0.882 atm, PH2 = 0.102 atm, PN2 = 0.161 atm, and Po2 = 0.00318 atm. (Recall that raising a number to the power of one-half is the same as taking its square root).
Chemistry
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Chapter1: Chemical Foundations
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![(Q75) The decomposition of gaseous nitric acid into its element is a nonspontaneous process with
a value for AG°rxn
of +73.5 kJ/mol for the process:
HNO3(g) --> 1/2 H2 (g) + 1/2 N2 (g) + 3/2 O2
(g).
What is the value of AGrxn if the reaction takes place at 727°C and the partial pressures of the
gases are:
PHNO3 = 0.882 atm, PH2 = 0.102 atm, PN2 = 0.161 atm, and Po2 = 0.00318 atm.
%3D
(Recall that raising a number to the power of one-half is the same as taking its square root).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0633024-a4bc-4f66-b9e9-fd2e8bdcc354%2F7e36eb00-2f7b-4abf-a9c3-5a1b8c3e7758%2Ff9jdtc_processed.png&w=3840&q=75)
Transcribed Image Text:(Q75) The decomposition of gaseous nitric acid into its element is a nonspontaneous process with
a value for AG°rxn
of +73.5 kJ/mol for the process:
HNO3(g) --> 1/2 H2 (g) + 1/2 N2 (g) + 3/2 O2
(g).
What is the value of AGrxn if the reaction takes place at 727°C and the partial pressures of the
gases are:
PHNO3 = 0.882 atm, PH2 = 0.102 atm, PN2 = 0.161 atm, and Po2 = 0.00318 atm.
%3D
(Recall that raising a number to the power of one-half is the same as taking its square root).
![(Q76) Was the deviation from standard conditions in the previous question (Q75) sufficient to
cause this process to become spontaneous?
Yes
No](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0633024-a4bc-4f66-b9e9-fd2e8bdcc354%2F7e36eb00-2f7b-4abf-a9c3-5a1b8c3e7758%2Fvf9dxmu_processed.png&w=3840&q=75)
Transcribed Image Text:(Q76) Was the deviation from standard conditions in the previous question (Q75) sufficient to
cause this process to become spontaneous?
Yes
No
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