For each reaction, find the value of ASº. Report the value with the appropriate sign. (a) 3 NO2(g) + H,O(1) → 2 HNO3(1) +NO(g) J/K (b) N2(g) + 3 F2(g) 2 NF3(g) J/K (c) C,H1,06(s) + 6 O2(g) 6 CO2(g) + 6 H,0(g) J/K

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### Calculating the Standard Entropy Change (ΔS°) for Chemical Reactions

To understand the spontaneity and feasibility of chemical reactions, it is important to calculate the standard entropy change (ΔS°). Entropy is a measure of disorder or randomness in a system. For each reaction below, you'll find the entropy change values (ΔS°) reported with the appropriate sign.

#### Reaction (a):

\[ 
3 \text{NO}_2(g) + \text{H}_2\text{O}(l) \rightarrow 2 \text{HNO}_3(l) + \text{NO}(g)
\]

**ΔS° Calculation:**

\[ \boxed{\text{J/K}} \]

#### Reaction (b):

\[ 
\text{N}_2(g) + 3 \text{F}_2(g) \rightarrow 2 \text{NF}_3(g)
\]  

**ΔS° Calculation:**

\[ \boxed{\text{J/K}} \]

#### Reaction (c):

\[ 
\text{C}_6\text{H}_12\text{O}_6(s) + 6 \text{O}_2(g) \rightarrow 6 \text{CO}_2(g) + 6 \text{H}_2\text{O}(g)
\] 

**ΔS° Calculation:**

\[ \boxed{\text{J/K}} \]

Make sure to perform the calculations based on the standard entropy values for each reactant and product involved in the reactions. The entropy change for a reaction can be calculated using the standard entropy values (S°) as follows:

\[ 
\Delta S° = \sum S°(\text{products}) - \sum S°(\text{reactants}) 
\]

In the space provided above (denoted by boxed regions), you would typically enter your computed value in Joules per Kelvin (J/K). 

### Understanding the Context:

**Graphs or Diagrams**: In this particular assignment, there are no graphs or diagrams present. 

Calculating the ΔS° for each reaction is a crucial step in thermodynamics as it helps in predicting whether a process will occur spontaneously. Positive values for ΔS° typically indicate increased disorder (favorable conditions) while negative values indicate decreased disorder.

Feel free to proceed with the calculations using the standard entropy values available in thermodynamic tables.
Transcribed Image Text:### Calculating the Standard Entropy Change (ΔS°) for Chemical Reactions To understand the spontaneity and feasibility of chemical reactions, it is important to calculate the standard entropy change (ΔS°). Entropy is a measure of disorder or randomness in a system. For each reaction below, you'll find the entropy change values (ΔS°) reported with the appropriate sign. #### Reaction (a): \[ 3 \text{NO}_2(g) + \text{H}_2\text{O}(l) \rightarrow 2 \text{HNO}_3(l) + \text{NO}(g) \] **ΔS° Calculation:** \[ \boxed{\text{J/K}} \] #### Reaction (b): \[ \text{N}_2(g) + 3 \text{F}_2(g) \rightarrow 2 \text{NF}_3(g) \] **ΔS° Calculation:** \[ \boxed{\text{J/K}} \] #### Reaction (c): \[ \text{C}_6\text{H}_12\text{O}_6(s) + 6 \text{O}_2(g) \rightarrow 6 \text{CO}_2(g) + 6 \text{H}_2\text{O}(g) \] **ΔS° Calculation:** \[ \boxed{\text{J/K}} \] Make sure to perform the calculations based on the standard entropy values for each reactant and product involved in the reactions. The entropy change for a reaction can be calculated using the standard entropy values (S°) as follows: \[ \Delta S° = \sum S°(\text{products}) - \sum S°(\text{reactants}) \] In the space provided above (denoted by boxed regions), you would typically enter your computed value in Joules per Kelvin (J/K). ### Understanding the Context: **Graphs or Diagrams**: In this particular assignment, there are no graphs or diagrams present. Calculating the ΔS° for each reaction is a crucial step in thermodynamics as it helps in predicting whether a process will occur spontaneously. Positive values for ΔS° typically indicate increased disorder (favorable conditions) while negative values indicate decreased disorder. Feel free to proceed with the calculations using the standard entropy values available in thermodynamic tables.
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