Q7) The current in(t) of Fig. 4 can be found as (mA): a) 12.5cos(500t - 0.107°) d) 12.5 cos(500t + 89.9°) 2000 2cos101 V 40 pa HE b) 12.5cos(500t+ 0.107°) e) 12.5 cos(500t+ 0.205°) 5 cos 10rV 20:2 PNY = 10.02 745.02 Fig. 3 10. 02 c) 12.5cos(500t - 89.9°) f) 12.5 cos(500t - 0.205°) 10052 cos5001 V 10.2 it Fig. 4 0.3 mH

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Q7) The current in(t) of Fig. 4 can be found as (mA):
a) 12.5cos(500t - 0.107°)
d) 12.5 cos(500t + 89.9°)
2cos101 V
2000
www
40
HE
Epa
b) 12.5cos(500t+ 0.107°)
e) 12.5 cos(500t +0.205°)
10.02
5 cos 10rV
20:2
71502
Fig. 3
100
c) 12.5cos(500t - 89.9°)
f) 12.5 cos(500t - 0.205°)
cos5001 V
1002
www
0.211
Fig. 4
0.3mH
Transcribed Image Text:Q7) The current in(t) of Fig. 4 can be found as (mA): a) 12.5cos(500t - 0.107°) d) 12.5 cos(500t + 89.9°) 2cos101 V 2000 www 40 HE Epa b) 12.5cos(500t+ 0.107°) e) 12.5 cos(500t +0.205°) 10.02 5 cos 10rV 20:2 71502 Fig. 3 100 c) 12.5cos(500t - 89.9°) f) 12.5 cos(500t - 0.205°) cos5001 V 1002 www 0.211 Fig. 4 0.3mH
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