### Dynamics of an Object Dropped Into a Hemisphere-Shaped Bowl**Scenario (Part b)**In this part of the question, the bowl is fixed on a cart. The total mass of the bowl and cart \( m_2 \) is the same as the point-like mass \( m_1 = m_2 = 1.09 \, \text{kg} \).Otherwise, the setup is the same as in part (a):An object of mass \( m_1 \) drops from rest from a height \( h = 5.84 \, \text{m} \) above the rim of a hemisphere-shaped bowl (i.e., a sphere cut in half at the equator). The hemisphere has a radius \( r = 1.96 \, \text{m} \). Treat the object as a point mass and neglect friction between the object and the bowl, as well as the friction between the cart and the floor.**Question:**What is the magnitude of the force the object exerts on the bowl when it is at the bottom of the bowl?**Hint:**You might wonder how the result can be different than in (a), but it is. Think carefully about which velocity is relevant to determine the force and how to obtain it for the setting described in part (b).**Diagram Explanation:**The diagram depicts the following elements:1. **Point Mass \( m_1 \)**: The object that drops from rest.2. **Height \( h \)**: The distance from which the object is dropped above the rim of the bowl, 5.84 m.3. **Radius \( r \)**: The radius of the hemisphere-shaped bowl, 1.96 m.4. **Bowl on Cart**: The bowl, fixed on a cart with a combined mass of 1.09 kg.The cart is illustrated with wheels, indicating that it can move, but friction between the cart and the floor is neglected for this analysis. Understanding the interaction between these components helps solve for the force exerted at the bottom of the bowl. ---### Educational Content: Physics Problem on Force and Motion#### Problem Statement**Q6a)** An object of mass \( m_1 = 1.09 \) kg, drops from rest from a height \( h = 5.84 \) m above the rim of a hemisphere-shaped bowl (i.e., a sphere cut in half at the equator). The hemisphere has a radius \( r = 1.96 \) m. Treat the object as a point mass and neglect any friction in the problem. In this part of the problem, the bowl is fixed to the surface of the earth. Assume \( g = 9.80 \) m/s².What is the magnitude of the force that the object exerts on the bowl when it is at the bottom of the bowl?#### Diagram ExplanationThe diagram accompanying the problem depicts the following:- A hemispherical bowl resting on a flat surface.- An object of mass \( m_1 \) located at a height \( h \) above the rim of the bowl.- The radius \( r \) of the hemispherical bowl is marked.- The distance \( h \) from the top of the bowl to the position of the object is indicated.- The bowl is shown as being perfectly symmetrical and fixed to the surface.The diagram aids in visualizing the problem setup, specifically the geometric relationship between the object, the height from which it is dropped, and the hemispherical bowl.#### Solution Steps (Guide for Students)1. **Initialize the Known Values:** - Mass of the object: \( m_1 = 1.09 \) kg - Height above the rim of the bowl: \( h = 5.84 \) m - Radius of the hemisphere: \( r = 1.96 \) m - Acceleration due to gravity: \( g = 9.80 \) m/s²2. **Calculate the Potential Energy Lost:** When the object is dropped, it loses potential energy equal to: \[ PE = m g H \] where \( H \) is the total height fallen, which is \((h + r)\).3. **Determine the Total Height Fallen:** \[ H = h + r = 5.84 \, \text{m} + 1.96 \, \text{m} = 7.

Mass of object Height from which it is thrown Radius of the bowl Acceleration due to gravity

Q6a) An object of mass m1 = 1.09 kg, drops from rest from a height h= 5.84 m above the rim of a hemisphere shaped bowl (i.e., a sphere cut in half at the equator). The hemisphere has a radius r = 1.96 m. Treat the object as a point mass and neglect any friction in the problem. In this part of the problem, the bowl is fixed to the surface of the earth. Assume g = 9.80. What is the magnitude of the force that the object exerts on the bowl when it is at the bottom of the bowl? m1

Q6a) An object of mass m1 = 1.09 kg, drops from rest from a height h= 5.84 m above the rim of a hemisphere shaped bowl (i.e., a sphere cut in half at the equator). The hemisphere has a radius r = 1.96 m. Treat the object as a point mass and neglect any friction in the problem. In this part of the problem, the bowl is fixed to the surface of the earth. Assume g = 9.80. What is the magnitude of the force that the object exerts on the bowl when it is at the bottom of the bowl? m1

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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