Q 6 please The following constants can be useful:Charge of electronMass of the electronMass of the protonlel = 1.6 x 10-1⁹ Cm, = 9.11x10 kg;m = 1.67x10-27 kg :Acceleration due to gravityPermittivity of free spaceCoulomb's constantπ = 3.14aChoose the best answer of the following questions (LIn the figure shown, if a = 10.0 cm, b = 40.0 cm,q= 6.0 μc, and Q = -10.0 μc. Answer questions 1,2 and 3.magnitude of the electric force (in N) between q and Q equals:C) 2.4B) 0.45D) 1.2he magnitude of the electric field ( in x 106 N/C) at point y is:C) 9.2B) 2.4) 1.8D) 3.6Q3. The magnitude of the electric potential (in KV) at point x is:A)-350B)-211C) 440D) 211E) 360Q4. A charge of 3 nC is located at the center of a cube of side length of 1 cm. The electric flux (in N.m²/C)through one surface is:A) 200B) 565C) 339D) 233Q5. In the figure shown, if C₁ = 9 µF, C₂ = 9 µF, C3 = 6 µF,then the equivalent capacitance (in µF) between the two points a and b is:A) 4.5B) 10C) 8.25D) 4E) 12Q6. The resistivity of a 4.0 m long copper wire is 1.72 x 10-8 2 m and its cross-sectional area is 2.0 x 10-6m². If the wire carries a current of 0.20 A, then the voltage difference (in mV) across the wire:.A) 1.57B) 6.9C) 1.7D) 0.79E) 2.55E) 524g = 9.8 m/s²8=8.85 x 10-12 c² / Nm²ke = 9 x 10⁹ N.m²/C²abE) -0.45E) 1.1C₁HHCzayC3b

Answered: Image /qna-images/answer/f4446a78-9967-458c-b45e-ec7994e04123.jpg

Q6. The resistivity of a 4.0 m long copper wire is 1.72 x 10-8 2 m and its cross-sectional area is 2.0 x 10-6 m². If the wire carries a current of 0.20 A, then the voltage difference (in mV) across the wire: D) 0.79 E) 2.55 61.57 B) 69 C) 1.7

Q6. The resistivity of a 4.0 m long copper wire is 1.72 x 10-8 2 m and its cross-sectional area is 2.0 x 10-6 m². If the wire carries a current of 0.20 A, then the voltage difference (in mV) across the wire: D) 0.79 E) 2.55 61.57 B) 69 C) 1.7

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

Question

Q 6 please

The following constants can be useful:
Charge of electron
Mass of the electron
Mass of the proton
lel = 1.6 x 10-1⁹ C
m, = 9.11x10 kg;
m = 1.67x10-27 kg :
Acceleration due to gravity
Permittivity of free space
Coulomb's constant
π = 3.14
a
Choose the best answer of the following questions (L
In the figure shown, if a = 10.0 cm, b = 40.0 cm,
q= 6.0 μc, and Q = -10.0 μc. Answer questions 1,2 and 3.
magnitude of the electric force (in N) between q and Q equals:
C) 2.4
B) 0.45
D) 1.2
he magnitude of the electric field ( in x 106 N/C) at point y is:
C) 9.2
B) 2.4
) 1.8
D) 3.6
Q3. The magnitude of the electric potential (in KV) at point x is:
A)-350
B)-211
C) 440
D) 211
E) 360
Q4. A charge of 3 nC is located at the center of a cube of side length of 1 cm. The electric flux (in N.m²/C)
through one surface is:
A) 200
B) 565
C) 339
D) 233
Q5. In the figure shown, if C₁ = 9 µF, C₂ = 9 µF, C3 = 6 µF,
then the equivalent capacitance (in µF) between the two points a and b is:
A) 4.5
B) 10
C) 8.25
D) 4
E) 12
Q6. The resistivity of a 4.0 m long copper wire is 1.72 x 10-8 2 m and its cross-sectional area is 2.0 x 10-6
m². If the wire carries a current of 0.20 A, then the voltage difference (in mV) across the wire:
.
A) 1.57
B) 6.9
C) 1.7
D) 0.79
E) 2.55
E) 524
g = 9.8 m/s²
8=8.85 x 10-12 c² / Nm²
ke = 9 x 10⁹ N.m²/C²
a
b
E) -0.45
E) 1.1
C₁
HH
Cz
a
y
C3
b

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