Q6Consider a system with four types of resources RI (3 units), R2 (2 units), R3 (3units), and R4 (2 units). A non-preemptive resource allocation policy is used. Atany given instance, a request is not entertained if it cannot be completely satisfied.Three processes P1, P2 and P3 request the resources as in Table Q6 if executedindependently.Process P1:units of R2t-0: requests 2t-1: requests 1unit of R3t-3requests 2units of Rt-5releases 1 unit of R2 and 1 unit of R1Table Q6t-7: releases 1 unit of R3;t-8: requests 2 units of R4t-10: FinishesProcess P2::requests 21 requenta 11 requests 1units of Riunit of R4unit of Rit-6: releases 1 unit of R3t-8: FinishesProcess PJ:t-0: requests 1 unit of R4requests 2 units of Alreleases 2 units of R1requests 1 unit of R2t-8: requests 1 unit of R3t-9: Finishest-2t-5t-7If all three processes run concurrently starting at time t - 0,Draw the resource allocation graph at the time:(i)t - 10Determine whether deadlock occurs or not. If yes, which processes are indeadlock?

Answer: We need to draw the resource allocation graph and check the whether deadlock occurs or not.…

Q6 Consider a system with four types of resources RI (3 units), R2 (2 units), R3 (3 units), and R4 (2 units). A non-preemptive resource allocation policy is used. At any given instance, a request is not entertained if it cannot be completely satisfied. Three processes P1, P2 and P3 request the resources as in Table Q6 if executed independently. Table Q6 Process P1:-- t-0: requests 2 units of R2 t-1: requests 1 unit of R3 units of R t-3: requests 2 t-5 releases 1 unit of R2 and 1 unit of R1 t-7: releases 1 unit of R3; t-8: requests 2 units of R t-10: Finishes Process P2: (b) - requests 2 units of Ri requests 1 unit of R4 requests 1 unit of Ri t-6 releases 1 unit of R3 t-8: Finishes Process PJ: t-0: requests 1 unit of R4 t-2 requests 2 units of Rl t-5: releases 2 units of R1 t-7 requests 1 unit of R2 t-8: requests 1 unit of R3 t-9: Finishes If all three processes run concurrently starting at time t - 0. Draw the resource allocation graph at the time: (i) (iii) t - 10 t-8 Determine whether deadlock occurs or not. If yes, which processes are in deadlock?

Q6 Consider a system with four types of resources RI (3 units), R2 (2 units), R3 (3 units), and R4 (2 units). A non-preemptive resource allocation policy is used. At any given instance, a request is not entertained if it cannot be completely satisfied. Three processes P1, P2 and P3 request the resources as in Table Q6 if executed independently. Table Q6 Process P1:-- t-0: requests 2 units of R2 t-1: requests 1 unit of R3 units of R t-3: requests 2 t-5 releases 1 unit of R2 and 1 unit of R1 t-7: releases 1 unit of R3; t-8: requests 2 units of R t-10: Finishes Process P2: (b) - requests 2 units of Ri requests 1 unit of R4 requests 1 unit of Ri t-6 releases 1 unit of R3 t-8: Finishes Process PJ: t-0: requests 1 unit of R4 t-2 requests 2 units of Rl t-5: releases 2 units of R1 t-7 requests 1 unit of R2 t-8: requests 1 unit of R3 t-9: Finishes If all three processes run concurrently starting at time t - 0. Draw the resource allocation graph at the time: (i) (iii) t - 10 t-8 Determine whether deadlock occurs or not. If yes, which processes are in deadlock?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Hash Table

A hash table also called a hash map, is a data structure that maps key-value pairs. The hash table can be used in complex systems to provide fast access and compact storage. A hash table is a structure that stores data in an abstract data type kind of associative array. It keeps data in an array format, with a distinct index value for every data value. If the index of the required data is known, then the data can be accessed very easily.

Question

Q6
Consider a system with four types of resources RI (3 units), R2 (2 units), R3 (3
units), and R4 (2 units). A non-preemptive resource allocation policy is used. At
any given instance, a request is not entertained if it cannot be completely satisfied.
Three processes P1, P2 and P3 request the resources as in Table Q6 if executed
independently.
Process P1:
units of R2
t-0: requests 2
t-1: requests 1
unit of R3
t-3
requests 2
units of R
t-5
releases 1 unit of R2 and 1 unit of R1
Table Q6
t-7: releases 1 unit of R3;
t-8: requests 2 units of R4
t-10: Finishes
Process P2:
:requests 2
1 requenta 1
1 requests 1
units of Ri
unit of R4
unit of Ri
t-6: releases 1 unit of R3
t-8: Finishes
Process PJ:
t-0: requests 1 unit of R4
requests 2 units of Al
releases 2 units of R1
requests 1 unit of R2
t-8: requests 1 unit of R3
t-9: Finishes
t-2
t-5
t-7
If all three processes run concurrently starting at time t - 0,
Draw the resource allocation graph at the time:
(i)
t - 10
Determine whether deadlock occurs or not. If yes, which processes are in
deadlock?

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Suppose that an operating system supports two kinds of sequential processes: high-priority interactive processes, and low-priority non-interactive processes. The behavior of the high-priority processes is to alternate between periods of computation of duration Tc and periods of blocking (waiting for input) of duration Tb. The behavior of the low-priority processes is to compute constantly, with no blocking. The operating system’s scheduling policy is round-robin with a quantum q, where Tc < q. Scheduling decisions are made only when a quantum expires, or when the running process blocks. The scheduler selects a low-priority process to run only if no high-priority processes are ready. Suppose there is one high-priority process and one low-priority process in the system, and that both processes will run for a long time. For what fraction of the time does the low-priority process run?
Suppose processes P1-P4 with the given priorities and resource allocations. 1 is the highest priority and 4 is the lowest priority. Let us also assume that the "no preemption" condition is now relaxed by allowing preemption of resources by processes of higher priority. For example, P3 may preempt P2 or P4 if it needs a resource which they are holding. If P3 preempts one of these processes, say P4, then P4 release all the resources it is holding. Show one sequence of events in which resources are allocated to the 4 processes and the resulting preemptions, if any, until all new requests are serviced. Current allocations are shown below. Each resource has 4 instances. Try to minimize the preemptions as they are expensive. Process ID Process Priority Current allocation New request R1 R2 R1 R2 P1 1 2 1 2 1 P2 3 0 1 1 0 P3 2 1 1 0 1 P4 4 1 1 2 1
Consider a computer environment in which there are 4 magnetic drives, 2 printers, 3 scanners, and 1 optical drive. Three processes P1, P2, P3 are using these resources. At any point in time, the allocations and requests for these resources are as follows. Allocations: Magnetic drive Printer Scanner Optical drive P1 1 P2 2 1 P3 1 Requests: Magnetic drive 2 Printer Scanner Optical drive P1 1 P2 1 1 P3 2 1 Is there any way that the processes can complete without deadlock? If yes, explain how. If not, explain why not.
In the following resource allocation graph, are the processes deadlocked? If “yes” explain why and state which processes are involved in deadlock. If “not” explain why.
I eant solution with step
In the following resource allocation graph, are the processes deadlocked? If “yes” explain why and state which processes are involved in deadlock. If “not” explain why.
Concurrent Processes / Monitors select which is true options: a CV (condition variable) queues in a monitor store suspended processes waiting on the corresponding condition. b The "Signal and Wait" approach (Hoare semantics) leads to more efficient implementation and reduces the number of context switches. c Two or more processes can be active in the same monitor simultaneously. d When the "Signal and Continue"-approach (Mesa semantics) is applied, the signaling process P continues executing. e The monitor-based solution to the Dining-Philosophers problem discussed in class is restricted to 5 philosophers.
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