Q5:1 A particle of mass m moves in a one dimensional potential U (x) where x < 0 0 < x < a U (x) = Vo x > a Sketch the potential. For E < Vo show that the energy eigenvalues are obtained from the equation VA – y² 2mVoa? tan ( y + 2 where y = ka and A= Y (Hint : Applying the boundary condition at = 0 'eliminates' the cos(kx) solution for 0 < x < a.)
Q5:1 A particle of mass m moves in a one dimensional potential U (x) where x < 0 0 < x < a U (x) = Vo x > a Sketch the potential. For E < Vo show that the energy eigenvalues are obtained from the equation VA – y² 2mVoa? tan ( y + 2 where y = ka and A= Y (Hint : Applying the boundary condition at = 0 'eliminates' the cos(kx) solution for 0 < x < a.)
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x < 0
0 < x < a
U (x) =
Vo
x > a
Sketch the potential.
For E < Vo show that the energy eigenvalues are obtained from the equation
VA – y²
2mVoa?
tan ( y +
2
where y = ka and A=
Y
(Hint : Applying the boundary condition at = 0 'eliminates' the cos(kx) solution for
0 < x < a.)"
Transcribed Image Text:Q5:1 A particle of mass m moves in a one dimensional potential U (x) where
x < 0
0 < x < a
U (x) =
Vo
x > a
Sketch the potential.
For E < Vo show that the energy eigenvalues are obtained from the equation
VA – y²
2mVoa?
tan ( y +
2
where y = ka and A=
Y
(Hint : Applying the boundary condition at = 0 'eliminates' the cos(kx) solution for
0 < x < a.)
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