Q5. As shown in the image below, the freight cars A and Bare approaching eachother, and they have a mass of mA = 19 Mg and mB = 12 Mg, respectively. Thedirections of their initial velocities are shown in the image, and the speeds are VA,1 =4.7 m/s and vB,1 = 1.2 m/s. If the two cars collide and get stuck together, determinethe loss of their combined kinetic energy (in kJ) during the collision. Please payattention: the numbers may change since they are randomized. Your answer mustinclude 1 place after the decimal point, and proper SI unit.VA,1AVB,1ВYour Answer:Answer

Given: The mass of the freight car A is mA = 19000 kg The mass of the freight car A is mB = 12000 kg…

Answered: Q5. As shown in the image below, the…

Similar questions

Ball A has a mass of 3 kg and is moving with a velocity of (vA)1 = 9 m/s when it makes a direct collision with ball B, which has a mass of 2.5 kg and is moving with a velocity of (vB)1 = 5 m/s . Suppose that e = 0.7. Neglect the size of the balls. a) Determine the velocity of A just after the collision measured to the right. (vA)2 = ? b) Determine the velocity of B just after the collision measured to the right. (vB)2 = ?
A-C thank you!
A 1000kg car is traveling 20m/s to the right when it collides head-on with a 1700kg pickup truck traveling 16m/s to the left. The vehicles lock together inelastically following the collision, which lasts 0.4s. What direction did the vehicles move after the collision? Car (initial) Truck (initial) Combined (final) Car only (final) Truck only (final) How fast were the vehicles moving after the collision? unit What was the magnitude of the impulse? unit What was the magnitude of the impact force? unit |pl unit |||
m₁ The figure shows two carts before a collision; cart m₁ is moving with velocity Vo toward cart m2 at rest. The carts slide without friction on the air track. (A) If the carts stick together when they collide, what will the final velocity be? (B) If the carts collide elastically, what will the final velocity of cart C₂ be? DATA: m₁ = 1.3 kg; m₂ {inelastic : } (in m/s) m₂ = 1.7 kg; {elastic } (in m/s) Vo = 2.5 m/s; A: 1.083 B: 1.268 OC: 1.483 D: 1.735 E: 2.030 OF: 2.375 G: 2.779 OH: 3.251 A: 1.608x10-¹OB: 2.331x10-¹ OC: 3.380x10¹ OD: 4.901x10-¹ E: 7.107x10¹ F: 1.031 G: 1.494 OH: 2.167
A truck with a mass of 1320 kg and moving with a speed of 12.0 m/s rear-ends a 703 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. Find the speed of both vehicles after the collision in meters per second. V car m/s %3D Vtruck m/s Additional Materials
James realizes that he can try to get Kevin by having two balls roll down from opposite hills. Ball one is 15kg and is being rolled down a hill of height 32m, ball two is 20kg, and is rolling down in the opposite direction from a height of 18.5m. What are their final velocities at the bottom of the hill? If they are now on a flat plane and collide in a completely elastic collision, what are their final speeds after the collision? (SHOW ALL WORK, UNITS AND FORMULAS USED)
Two cars are sent towards each other with masses and velocities shown. After colliding and bouncing off each other, what is the velocity of the 0.7 kg car ? Ignore friction and air resistance.
A student is performing a series of experiments where he hits two toy cars together and records the initial and final velocities of each. Using the data he collected below, how does the total momentum before the cars hit compare to the total momentum after?(answer choices in the 2nd screenshot)
T3.29 Please help me answer this physics question.
5. Two balls, A and B, each of mass 1.0 kg, initially travel at the velocities VA = (10î + 20ĵ ) m/s and Vg = (-10î + 5j ) m/s, respectively. Immediately after their collision V = (-3î + 15j ) m/s. No net external force acts on the two balls. %3D What is the final velocity of ball A? What is the change in the balls' total kinetic energy?
For all the collisions in this lab, what can you conclude about the sum of the changes in momentum for the objects (Δp1 + Δp2 for Parts 1 and 2 and Δp1 + Δp2 + Δp3 for Part 3)? Does this agree with the Law of Momentum Conservation? Show why or why not.
m2 m h=7.0m ☐ Figure 1: Diagram for Problem 15 15) During a test investigation, a 40-gram bullet is fired towards a stationary block of 1.0-kg mass causing a perfectly in-elastic collision. After the collision, the block-bullet system slides up a smooth ramp, eventually coming to rest at an elevation of 7.0 meters. Calculate the speed of the bullet. Must show all steps including the equations being used.

SEE MORE QUESTIONS