Q5: Answer the following: A. A base station has 40 dBm maximum power per link, antenna height of 35m and an antenna gain of 10dB. For mobiles served by this base station all have 2m antenna height, 3 dB antenna gain, and the largest separating distance for 900MHz frequency in Urban area is 10.6 km. Calculate the receiver sensitively and the largest distance in Rural area? B. CDMA technique requires several levels of synchronization. Explain? Lsuburban (dB) = L(Urban) - 2 [Log()]-5.4 LRural (dB) = L(Urban) - 4.78(Log(f.))² + 18.33Log(fc) - 40.94 LUrban (dB)=69.55+26.16 Log (f.) - 13.82Log (hte) - a(hre) + (44.9-6.55Log(he)) Log(d) = a(hre) (1.1 Log(fe)-0.7)hre - (1.56 Log(fc) - 0.8)dB a(hre) = 8.29(Log (1.54hre))² - 1.1dB a(hre) = 3.2(Log (11.75hre))² - 4.97dB for f 300 MHz for f > 300 MHz

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Mobile communication 

Q5: Answer the following:
A. A base station has 40 dBm maximum power per link, antenna height of
35m and an antenna gain of 10dB. For mobiles served by this base station all have
2m antenna height, 3 dB antenna gain, and the largest separating distance for
900MHz frequency in Urban area is 10.6 km. Calculate the receiver sensitively
and the largest distance in Rural area?
B. CDMA technique requires several levels of synchronization. Explain?
Lsuburban (dB) = L(Urban) - 2 [Log()]-5.4
LRural (dB) = L(Urban) - 4.78(Log(f.))² + 18.33Log(fc) - 40.94
LUrban (dB)=69.55+26.16 Log (f.) - 13.82Log (hte) - a(hre) + (44.9-6.55Log(he)) Log(d)
=
a(hre) (1.1 Log(fe)-0.7)hre - (1.56 Log(fc) - 0.8)dB
a(hre) = 8.29(Log (1.54hre))² - 1.1dB
a(hre) = 3.2(Log (11.75hre))² - 4.97dB
for f 300 MHz
for f > 300 MHz
Transcribed Image Text:Q5: Answer the following: A. A base station has 40 dBm maximum power per link, antenna height of 35m and an antenna gain of 10dB. For mobiles served by this base station all have 2m antenna height, 3 dB antenna gain, and the largest separating distance for 900MHz frequency in Urban area is 10.6 km. Calculate the receiver sensitively and the largest distance in Rural area? B. CDMA technique requires several levels of synchronization. Explain? Lsuburban (dB) = L(Urban) - 2 [Log()]-5.4 LRural (dB) = L(Urban) - 4.78(Log(f.))² + 18.33Log(fc) - 40.94 LUrban (dB)=69.55+26.16 Log (f.) - 13.82Log (hte) - a(hre) + (44.9-6.55Log(he)) Log(d) = a(hre) (1.1 Log(fe)-0.7)hre - (1.56 Log(fc) - 0.8)dB a(hre) = 8.29(Log (1.54hre))² - 1.1dB a(hre) = 3.2(Log (11.75hre))² - 4.97dB for f 300 MHz for f > 300 MHz
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