Q5-(A)- The all-day efficiency 200 KVA transformer is 96% when it is loaded follows 12 hours 8 hours 120 k w at p.f. 0.8 lag 80kw at p.f. 0.8 lag 4 hours No load If maximum efficiency of this transformer is 96.8% at 80% of load with unity p.f. Find iron loss and full load copper loss fel fil (B)- Explain briefly, How can be minimized the core lossés in transformer

Q5-(A)- The all-day efficiency 200 KVA transformer is 96% when it is loaded follows 12 hours 8 hours 120 k w at p.f. 0.8 lag 80kw at p.f. 0.8 lag 4 hours No load If maximum efficiency of this transformer is 96.8% at 80% of load with unity p.f. Find iron loss and full load copper loss fel fil (B)- Explain briefly, How can be minimized the core lossés in transformer

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.11MCQ: For a short-circuit test on a 2-winding transformer, with one winding shorted, can you apply the...

See similar textbooks

Related questions

Q: Below is a time current curve (TCC), showing the damage curve of a transformer. Draw (roughly),…

A: TCC- Time Current Curve is a plot shows the overcurrent device's interruption time which is based on…

Q: You have been assigned to select a transformer to supply a peak power of 100 kW to a load that draws…

A: Given a transformer is supplying the peak load of 100 kw for small time and very less load in the…

Q: For the transformer below determine the magnitude for the induced secondary voltage if: Ep = 1kV Np…

Q: The table below shows some performance parameters of a certain power transformer. Full-load voltage…

Q: How do i calculate secondary current in transformer analysis

A: Given that calculate secondary current in transformer analysis

Q: t = 0 2 kQ 18 k2 150 µF. Vc 4 k2 18 V + I

Q: What are the advantages of Delta connection in high power transformer?

A: Transformer : It is an electrical device used to transform the voltage from one level to another.…

Q: Which of the following are power losses that can occur in a practical transformer (non-ideal)?…

Concept explainers

Distribution System

The final stage in the delivery of the electric power is the electric power distribution system. From the transmission system to the individual customers it carries electricity. The distribution system is connected with the transmission system and is used to lower the voltage of the transmission to medium voltage in the range of 2 kV to 35 kV with the help of transformers. This medium voltage to the distribution transformers located near the customer's premises is carried by the primary distribution system lines. These distribution transformers in turn lower the voltage to utilization voltage used in lightings, household appliances, industrial equipments etc. Through secondary distribution lines often several customers are supplied from one transformer. It is through service drops, the commercial and residential customers are connected to the secondary distribution system lines. Customers who demand a larger amount of power can be connected directly to the primary distribution system level or the sub-transmission level.

Question

Q5-(A)- The all-day efficiency 200 KVA transformer is 96% when it is loaded follows
12 hours
8 hours
120 k w at p.f. 0.8 lag
80kw at p.f. 0.8 lag
4 hours
No load
If maximum efficiency of this transformer is 96.8% at 80% of load with unity p.f.
Find iron loss and full load copper loss
Pel F.L
(B)- Explain briefly, How can be minimized the core lossés in transformer
se

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

An ideal transformer has no real or reactive power loss. (a) True (b) False
The symbol shown is a(n) a. iron core transformer. b. auto transformer. c. current transformer. d. air core transformer.
For an ideal transformer, the efficiency is (a) 0 (b) 100 (c) 50
Consider an ideal transformer with N1=3000andN2=1000 turns. Let winding 1 be connected to a source whose voltage is e1(t)=100(1| t |)volts for 1t1ande1(t)=0 for | t |1 second. A2- farad capacitor is connected across winding 2. Sketch e1(t),e2(t),i1(t),andi2(t) versus time t.
For an ideal 2-winding transformer, an impedance Z2 connected across winding 2 (secondary) is referred to winding 1 (primary) by multiplying Z2 by (a) The turns ratio (N1/N2) (b) The square of the turns ratio (N1/N2)2 (c) The cubed turns ratio (N1/N2)3
A single-phase, 50-kVA,2400/240-V,60-Hz distribution transformer has the following parameters: Resistance of the 2400-V winding: R1=0.75 Resistance of the 240-V winding: R2=0.0075 Leakage reactance of the 2400-V winding: X1=1.0 Leakage reactance of the 240-V winding: X2=0.01 Exciting admittance on the 240-V side =0.003j0.02S (a) Draw the equivalent circuit referred to the high-voltage side of the transformer. (b) Draw the equivalent circuit referred to the low-voltage side of the transformer. Show the numerical values of impedances on the equivalent circuits.
A 23/230-kV step-up transformer feeds a three-phase transmission line, which in turn supplies a 150-MVA,0.8 lagging power factor load through a step-down 230/23-kV transformer. The impedance of the line and transformers at 230kVis18+j60. Determine the tap setting for each transformer to maintain the voltage at the load at 23 kV.
A single-phase step-down transformer is rated 13MVA,66kV/11.5kV. With the 11.5 kV winding short-circuited, rated current flows when the voltage applied to the primary is 5.5 kV. The power input is read as 100 kW. Determine Req1andXeq1 in ohms referred to the high-voltage winding.
Consider the three single-phase two-winding transformers shown in Figure 3.37. The high-voltage windings are connected in Y. (a) For the low-voltage side, connect the windings in , place the polarity marks, and label the terminals a, b, and c in accordance with the American standard. (b) Relabel the terminals a, b, and c such that VAN is 90 out of phase with Va for positive sequence.
For the transformer in Problem 3.10. The open-circuit test with 11.5 kV applied results in a power input of 65 kW and a current of 30 A. Compute the values for GcandBm in siemens referred to the high-voltage winding. Compute the efficiency of the transformer for a load of 10 MW at 0.8 p.f. lagging at rated voltage.
The ratings of a three-phase three-winding transformer are Primary(1): Y connected 66kV,15MVA Secondary (2): Y connected, 13.2kV,10MVA Tertiary (3): A connected, 2.3kV,5MVA Neglecting winding resistances and exciting current, the per-unit leakage reactances are X12=0.08 on a 15-MVA,66-kV base X13=0.10 on a 15-MVA,66-kV base X23=0.09 on a 10-MVA,13.2-kV base (a) Determine the per-unit reactances X1,X2,X3 of the equivalent circuit on a 15-MVA,66-kV base at the primary terminals. (b) Purely resistive loads of 7.5 MW at 13.2 kV and 5 MW at 2.3kV are connected to the secondary and tertiary sides of the transformer, respectively. Draw the per- unit impedance diagram, showing the per-unit impedances on a 15-MVA,66-kV base at the primary terminals.
(a) An ideal single-phase two-winding transformer with turns ratio at=N1/N2 is connected with a series impedance Z2 across winding 2. If one wants to replace Z2, with a series impedance Z1 across winding 1 and keep the terminal behavior of the two circuits to be identical, find Z1 in terms of Z2. (b) Would the above result be true if instead of a series impedance there is a shunt impedance? (c) Can one refer a ladder network on the secondary (2) side to the primary (1) side simply by multiplying every impedance byat2 ?