Q4/Convert to assembly program A/W=(A-B)+(A-C)+(A-C)^A
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- 2. Write the assembly code for the following high-level pseudo code: if ((a>=b) AND (b==c)) OR (a<=c) then a =b+c else a = b -cGiven the following code segment in C++, please write its corresponding 68K assembly code. int sum = 0; int c =1; for (unsigned short i = 0; i <= 10; i++) { if (c == 1 ) { sum += i; c = 0; } else { c = 1; } }Question 2 Convert the following C code into ARM assembly code. // x in X1, y in X2, return sum in X0 int sum(int x, int y) { int i; int sum = for(i=x; i1- For the following C statement, what is the corresponding RISC-V assembly code? Assume that the variables x, y, h, and i are given and could be considered integers as declared in a C program. Use a minimal number of assembly instructions. Also, use the variables as opposed to register values. h = (x - y) + (i-1) 2- For the following RISC-V assembly instructions below, what is a single corresponding C statement? Assume f, g, h, i are in x18, x19, x20 and x21. Your answer must be one single C statement for all assembly instructions as opposed to one C statement for each assembly instruction. sub x18, x19, x20 add x18, x18, x21 3- Registers in RISC-V are 64-bit. For the sake of simplicity, consider the following instructions operating on 32-bit registers. Assume that registers x5 and x6 hold the values 0xBBBBBBBB and 0x00000000, respectively. - What is the value in x6 for the following slli x6, x5, 6 - Using the result from the part above, what is the value in x6 for the following…Convert the following high-level code snippets into RISC-V assembly language. Assume that the (signed) integer variables g and h are in registers a0 and a1, respectively. Clearly comment your code.Write the following sequence of code into RISC-V assembler. Assume that x, y, and z are stored in registers x18, x19, and x20 respectively. x = y + 2; z = x – z - 2;For the following C statement, write the corresponding RISC-V assembly code. Assume that the base addresses of long long int arrays A and B are in registers x6 and x7 respectively. Each element of A or B is 8 bytes, and the variables i and j are assigned to registers x5 and x10 respectively. j = B[A[i*2]] - 16;Convert the C code below into RISC-V assembly language for the following two scenarios: a) Variable fis assigned to register x5. b) Variable fis assigned to register x20 Arguments a and b are available in x10 and x11 according to RISC-V convention. The return value is stored in x10 according to RISC-V convention. Return address is available in x1. Note: avoid unnecessary write operations to Stack memory long long int leaf_example (long long int a, long long int b) { long long int f; if (a == b) f=a + b; else f=a – b; return f; }Translate the following C code to MIPS assembly. Assume that the integer i is stored register $s0, and that the base addresses of integer arrays A and B are stored in registers $sl and $s2 respectively. for (i=0;i<10;i++) A[i]-B[i]+5;SEE MORE QUESTIONS
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