Convert the following C code to MIPS assemblymain () {int i, size = 10, sum, pos, neg;int arr[10] = (12, -1, 8, 0, 6, 85, -74, 23, 99, -30}:sum =pos =neg%3!for (i = 0; i < size; i++) {sum += arr[i]:if (arr[i] > 0)pos += arr[i]:if (arr[i] < 0)neg + arr[i]:return 0;

The question is to write MIPS code for the given C code.

Convert the following C code to MIPS assembly main () { int i, size = 10, sum, pos, neg; int arr[10] = (12, -1, 8, o, 6, 85, -74, 23, 99, -30}: sum = 0; pos = 0; neg = for (i = 0; i < size; i++) { sum += arr[i]; if (arr[i] > 0) pos += arr [i]; if (arr[i] < 0) neg + arr[i]: return 0;

Convert the following C code to MIPS assembly main () { int i, size = 10, sum, pos, neg; int arr[10] = (12, -1, 8, o, 6, 85, -74, 23, 99, -30}: sum = 0; pos = 0; neg = for (i = 0; i < size; i++) { sum += arr[i]; if (arr[i] > 0) pos += arr [i]; if (arr[i] < 0) neg + arr[i]: return 0;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Q: 1. Convert the following C code to MIPS assembly. Use the proper procedure/function calline…

A: C language is simple and closely related to machine language. Thus, C acts as an algorithm or…

Q: the C code of the following MIPS Compiler: bne $s3, $s4, Else add $s0, $s1, $s2…

A: It is defined as a general-purpose programming language that is extremely popular, simple, and…

Q: use SSE instructions to add 12 floating point numbers. int main(int c, char** s) { float ary[] =…

A: SSE instructions are an extension of the SIMD execution model introduced in MMX technology. SSE…

Q: 2) Translate the function origami into a MIPS assembly code fragment: int origami (int AD, int BO,…

A: origami: addiu $sp,$sp,-32 sw $fp,28($sp) move $fp,$sp sw…

Q: Using the following C code and assembly code answer the following; C: long int…

A: C, known for its simplicity and power, is the most widely used programming language.In particular,…

Q: This is what I have so far I need help with the commenting on the assembly code I have included…

A: Assembly code, also known as assembly language, is a low-level programming language that is closely…

Q: Translating this C code into assembly language, draw the stack for this function. Suppose the…

A: The assembly language program for above said function can be written as follows func(int, char):…

Q: X. Consider the following C functions and assembly code Assume that int is 32 bits, short is 16…

A: Here we have given the correct option with suitable code. You can find the solution in step 2.

Q: Course Computer Architecture and Organization) Using MARS simulator, write the equivalent assembly…

A: The first line of the assembly code defines the data section where the variables are stored.

Q: Convert the following program into Pep/9 assembly code: #include using namespace std; const…

A: The Pep/9 computer is a 16-bit complex instruction set computer (CISC). It is designed to teach…

Q: Explain how to work the following statement in Assembly language. movf i,w iorwf…

A: Here is the answer with explanation:-

Q: Draw a block diagram of the system with inputs and outputs labeled.

A: : Block diagram is a diagram of a system that represents the connection between the function of the…

Q: Please change this C code to Assembly program(x86 and ARM assembly gcc) #include int main() {…

A: We have a C language program to find prime numbers to a range. We need to convert this C language…

Q: Create a simple data program with a minimum of [3][4] for a two dimensional Array

A: A linear way collection of same type of data items are called ARRAYS.It store multiple values but of…

Q: please translate the following c program to pep 9 assembly language. void printMin(int a, int b) {…

A: The question has been answered in step2

Q: Please use C++ to code a multi-threaded sieve of Eratosthenes program using MP

A: Note that this code uses the MP library for multi-threading, which provides an easy interface for…

Q: Translate the following C strlen function to RISC-V assembly in two differ using pointers once).…

A: Dear Student, The answer to your question with required explanations is given below -

Q: Q.7 Write each of the following pseudocode in assembly language and explain: (a) if( varl >= var2 )…

A: Given: We are given a piece of code that contains control statements. Goal: We have to write the…

Q: Convert the following C code into ARM assembly code. n in X1, return count in XO int even(int n) {…

A: The method involved with utilizing a constructing agent like as to change over from (ARM) low level…

Q: unsigned char A, B, C; C = C + 2; if (A > B) elseif (A == B) C = C + 1; else %3D C = 0; %3D

A: To do: Convert C code to assembly Language

Q: label in the middle of an instruction 1 order(int Int): 2 addi sd sd sp, sp, -64 ra, 56(sp) se,…

A: RISC-V is an instruction set language which is based on RISC (Reduced Instruction Set Computer)…

Q: Convert the following C code into ARM assembly code. // pointer to v in X1, n in X2, return prod in…

A: Given code: //pointer to v in X1, n in X2, return prod in X0 double arraytimes(double *v,int n){…

Q: // Example 8.27a void Func(int a[], int & r) { int i; for (i = 0; i < 100; i++) { a[i] = r + i/2;…

A: The solution is given below for the above given question:

Q: Q3. Factorial (Iterative algorithm) - Use Q1 Get a user input of one non-negative integer numbers: A…

A: The code is given INPUTSTORE xSubt oneSTORE pstore yloop, LOAD xADD multiplySTORE multiplyLOAD…

Q: Convert the following C code to MIPSzy assembly

A: Microprocessor without Interlocked Pipeline Stages is referred to as MIPS.MIPS Technologies created…

Q: A programmer is asked to translate the following HLL code into MIPS Assembly language int isa() =…

A: code.asm .data isa: .word 10,20,30,-5,-15,40,50,-88,19,-33 hud: .asciiz "***" .text .globl bonus…

Q: For the following C statement, what is the corresponding MIPS assembly code? Assume that the…

A: The below answer provides the MIPS assembly code for the following C statement: B[f-j] = B[i] +…

Q: Using the following C code and assembly code answer the following; C: long int…

A: The provided C code and assembly code depict a function named nothingGreater in both C and x86-64…

Q: 1)Write the following code segment in MARIE assembly and test it. int x, y; scanf(“%d”, &x); If…

A: The MARIE assembly language of the code segment is:ORG 100INPUTSTORE xSUBT oneSKIPCOND 800JUMP…

Q: Consider the following C function: void f(int **, int a, int b) { if (x != 0) { *x += a; } return; }…

A: Even though most programming is now carried out in high level languages, a good understanding of the…

Q: Please make sure the assembly file can work in SPIM

A: First of lets correct the code for converting the decimal in binary: The code has following error…

Q: Question Description Consider the following C function: long func(long x, long y, long z) { long…

A: Solution: Given, long func(long x, long y, long z) { long ti = x + 3; long t2 - 2 + ti; long t3…

Q: const numLoops = 10;

A: #include <iostream> using namespace std; const numLoops = 10; int main() { int x = 0; do…

Q: Step 1: Convert the assembly code into C++ code. Step 2: Explain the function of the converted C++…

A: Solution 1:

Q: int func (int a, int b, int c){ if (a<=c) return 4; else if (a<b) return 8 else return a+c

A: Converting c code to RISC -V is a hectic task , but the function provided here is a bit easy, we…

Q: a=0.0; i=10; while (i>0) { i=i-1; a=a*B[i]; } where a is a single-precision floating-point number…

A: sub.s $f0, $f0, $f0 #single precision floating point for subtraction operations addi…

Q: he portion of the generated assembly code implementing the C function int (int x, int y, int z) is…

A: Request : If u are satisfied with the solution please upvote please Don't downvote if you have…

Concept explainers

Computer Fundamentals

The computer is termed computation. For calculating or computing something the device that has been used is known as the computer. Or we can say that for performing a fast arithmetic operation the device that has been used is a computer. Storing, processing, and retrieving are the main features of a computer. 

Question

Convert the following C code to MIPS assembly
main () {
int i, size = 10, sum, pos, neg;
int arr[10] = (12, -1, 8, 0, 6, 85, -74, 23, 99, -30}:
sum =
pos =
neg
%3!
for (i = 0; i < size; i++) {
sum += arr[i]:
if (arr[i] > 0)
pos += arr[i]:
if (arr[i] < 0)
neg + arr[i]:
return 0;

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions

Implement the following C recursive function using RISC-V instructions. Use x6 to store the value of n. The return result should also be in x6. long long int func1 (long long int n) { if (n < 1) return 0; else return n + func1(n - 2); }
Develop a c program that accept 4 array elements 100,200,300,400 as input and display the average of array elements.
Answer properly acc to 18 marks in detail
Using the following C code and assembly code answer the following; C: long int nothingGreater(long int num) { if (num > 240) { return 240 - num; } else { return num; } } Assembly: 0x00000000004004ed <+0>: push %rbp 0x00000000004004ee <+1>: mov %rsp,%rbp 0x00000000004004f1 <+4>: mov %rdi,-0x8(%rbp) 0x00000000004004f5 <+8>: cmpq $0xf0,-0x8(%rbp) 0x00000000004004fd <+16>: jle 0x40050a <nothingGreater+29> 0x00000000004004ff <+18>: mov $0xf0,%eax 0x0000000000400504 <+23>: sub -0x8(%rbp),%rax 0x0000000000400508 <+27>: jmp 0x40050e <nothingGreater+33> 0x000000000040050a <+29>: mov -0x8(%rbp),%rax 0x000000000040050e <+33>: pop %rbp 0x000000000040050f <+34>: retq a. What's the starting address of nothingGreater in memory (specify in hex starting with 0x; you may omit leading zeroes)? b. What register is the argument stored in when the function starts (give the 3-letter abbreviation with a % beforehand)?
please answer with proper explanation and step by step solution.
write the mips assembly code
write an assembly program that has two functions, in first function shows the number in reverse order (number should be 412) and in second function, evaluate any expression (e.g 1+2*2) using stack.
Using the following C code and assembly code answer the following; C: long int nothingGreater(long int num) { if (num > 240) { return 240 - num; } else { return num; } } Assembly: 0x00000000004004ed <+0>: push %rbp 0x00000000004004ee <+1>: mov %rsp,%rbp 0x00000000004004f1 <+4>: mov %rdi,-0x8(%rbp) 0x00000000004004f5 <+8>: cmpq $0xf0,-0x8(%rbp) 0x00000000004004fd <+16>: jle 0x40050a <nothingGreater+29> 0x00000000004004ff <+18>: mov $0xf0,%eax 0x0000000000400504 <+23>: sub -0x8(%rbp),%rax 0x0000000000400508 <+27>: jmp 0x40050e <nothingGreater+33> 0x000000000040050a <+29>: mov -0x8(%rbp),%rax 0x000000000040050e <+33>: pop %rbp 0x000000000040050f <+34>: retq What are the memory addresses of the three statements that implement the if statement (provide hex addresses with 0x prefix and without leading zeroes)? The first two statements that work together: The third statement that skips the else code if the if…
Translate given C code to assembly. Write a complete program in assembly (Do not use data segment in your code) c=0; b=7; do { C++; b--; printf("A\n"); } while (c
I want to translate the following C code into MIPS assembly Also, assume the base address of A[0] is stored at $s0 Also assume that every element of the array A is a 4-byte integer int k = 5; while (k > 0){ A[k] = A[k] + k; k = k – 1;}
18. or the following C code write assembly code as appropriate, using LDR and STR for load and store: if (a > b) else x = a; x = b;
1. Convert the following C code into MIPS assembly: void array_comp(int num) { int array [10]; int i; for (i=0; i= 0) return 1; else return 0; int sub (int a, int b) { return a-b; }