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- c++ coding language I need help with part B and C please. If you are unable to do both, then PLEASE prioritize part C. I am really stuck and really can use the help. This is the code for c that was provided in order to guide me: const int N =31; // N parking spaces bool parking[N]; // the garage void EmptyTheLot(bool parking[], int N) { for(int i=0; i<N; i++) p[i]=false; // empty space } // returns -1 if no space found, //otherwise it returns 0<=i<N for a valid space. int FindSpace(int PlateNumber, bool parking[], int N) { // ????? } main() { EmptyTheLot(parking, N); // start with an empty parking garage. // get plate numbers and fill lot. }C++ complete and create magical square #include <iostream> using namespace std; class Vec {public:Vec(){ }int size(){return this->sz;} int capacity(){return this->cap;} void reserve( int n ){// TODO:// (0) check the n should be > size, otherwise// ignore this action.if ( n > sz ){// (1) create a new int array which size is n// and get its addressint *newarr = new int[n];// (2) use for loop to copy the old array to the// new array // (3) update the variable to the new address // (4) delete old arraydelete[] oldarr; } } void push_back( int v ){// TODO: if ( sz == cap ){cap *= 2; reserve(cap);} // complete others } int at( int idx ){ } private:int *arr;int sz = 0;int cap = 0; }; int main(){Vec v;v.reserve(10);v.push_back(3);v.push_back(2);cout << v.size() << endl; // 2cout << v.capacity() << endl; // 10v.push_back(3);v.push_back(2);v.push_back(3);v.push_back(4);v.push_back(3);v.push_back(7);v.push_back(3);v.push_back(8);v.push_back(2);cout…oop using c++ please give me full answer thanks Write a Program that implements Base class calculator and a Derived class scientific calculator, The Derived class should take the basic operations i.e. add, divide, subtract from calculator. However it should have its own methods such as square root.
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- Unit ConversionWrite a unit conversion program in C++ that asks the users from which unit they want to convert(gal, oz, lb, ft, mi) and to which unit they want to convert (l, g, kg, m, km). Rejectincompatible conversions (such as gal → km). Ask for the value to be converted, thendisplay the result:Convert from? galConvert to? mlValue? 2.52.5 gal = 9462.5 mlC++ #include <string>#include <cmath> class DollarAmount {public:// initialize amount from an int64_t valueexplicit DollarAmount(int64_t value) : amount{value} { } // add right's amount to this object's amountvoid add(DollarAmount right) {// can access private data of other objects of the same classamount += right.amount; } // subtract right's amount from this object's amountvoid subtract(DollarAmount right) {// can access private data of other objects of the same classamount -= right.amount;} // uses integer arithmetic to calculate interest amount, // then calls add with the interest amountvoid addInterest(int rate, int divisor) {// create DollarAmount representing the interestDollarAmount interest{(amount * rate + divisor / 2) / divisor}; add(interest); // add interest to this object's amount} // return a string representation of a DollarAmount objectstd::string toString() const {std::string dollars{std::to_string(amount / 100)};std::string…C PROGRAM Reverse + Random Formula In the code editor, there's already an initial code that contains the function declaration of the function, computeReverseNumber(int n) and an empty main() function. For this problem, you are task to implement the computeReverseNumber function. This function will take in an integer n as its parameter. This will get the reverse of the passed integer and will then compute and return the value: result = (original_number + reverse_of_the_number) / 3 In the main() function, ask the user to input the value of n, call the function computeReverseNumber and pass the inputted value of n, and print the result in the main() with two (2) decimal places. SAMPLE: Input n: 20 Output: 7.33 Input n: 123 Output: 148.00