Q4: By using the General flow equation: 0.6 38.77F GT,LZ For two parallel gas pipelines (1- BCE & 2-BDE ) as shown in figure determine a formula can be used to calculate the equivalent pipe diameter: イ D' am. Note: friction factor can be calculated from: f- (0.0396/ Re")

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Q4: By using the General flow equation:
0.5
Q = 38.77F
P² – P2
(
GT;LZ
For two parallel gas pipelines (1- BCE & 2-BDE ) as shown in figure determine a formula
can be used to calculate the equivalent pipe diameter:
イ
Note: friction factor can be calculated from : f=(0.0396/ Re)
Transcribed Image Text:Q4: By using the General flow equation: 0.5 Q = 38.77F P² – P2 ( GT;LZ For two parallel gas pipelines (1- BCE & 2-BDE ) as shown in figure determine a formula can be used to calculate the equivalent pipe diameter: イ Note: friction factor can be calculated from : f=(0.0396/ Re)
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