Q4// A ring of a mean diameter 30 cm and cross sectional area of 15 cm2 is made up of semi – circular sections of cast iron and cast steel. If each joint has an air gap of 0.25 mm. Find amper turns required to produce a flux of 7 x 10 weber in the magnetic circuit. The relative permeability of steel and iron are 852 and 165 respectively. - OA- Amper turns required= 1105 OB- Amper turns required= 1995 OC- Amper turns required= 2250 OD- Amper turns required= 3150 OE- None of above ارسال الاجابة

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Q4// A ring of a mean diameter 30 cm
and cross sectional area of 15 cm2 is
made up of semi – circular sections of
cast iron and cast steel. If each joint
has an air gap of 0.25 mm. Find amper
turns required to produce a flux of 7 x
10 weber in the magnetic circuit. The
relative permeability of steel and iron
are 852 and 165 respectively.
-
OA- Amper turns required= 1105
OB- Amper turns required= 1995
OC- Amper turns required= 2250
OD- Amper turns required= 3150
OE- None of above
ارسال الاجابة
Transcribed Image Text:Q4// A ring of a mean diameter 30 cm and cross sectional area of 15 cm2 is made up of semi – circular sections of cast iron and cast steel. If each joint has an air gap of 0.25 mm. Find amper turns required to produce a flux of 7 x 10 weber in the magnetic circuit. The relative permeability of steel and iron are 852 and 165 respectively. - OA- Amper turns required= 1105 OB- Amper turns required= 1995 OC- Amper turns required= 2250 OD- Amper turns required= 3150 OE- None of above ارسال الاجابة
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