Q3 with a mean value of of ux = 1300 kN and a coefficient of variation of ôx = 0.20. The capacity (X) of an isolated spread footing under a column is modeled by a normal distribution a) If the column is subjected to a load of 600 kN, calculate the probability of failure of the foundation. (see the figure below) b) If the failure probability of the foundation needs to be limited to 0.03, what is the maximum load that can be applied to the column? Load = 600 kN X=Capacity (resistance)

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Q3
The capacity (X) of an isolated spread footing under a column is modeled by a normal distribution
with a mean value of of ux = 1300 kN and a coefficient of variation of 8x = 0.20.
a) If the column is subjected to a load of 600 kN, calculate the probability of failure of the foundation. (see the
figure below)
b) If the failure probability of the foundation needs to be limited to 0.03, what is the maximum load that can be
applied to the column?
Load = 600 kN
X=Capacity (resistance)
Transcribed Image Text:Q3 The capacity (X) of an isolated spread footing under a column is modeled by a normal distribution with a mean value of of ux = 1300 kN and a coefficient of variation of 8x = 0.20. a) If the column is subjected to a load of 600 kN, calculate the probability of failure of the foundation. (see the figure below) b) If the failure probability of the foundation needs to be limited to 0.03, what is the maximum load that can be applied to the column? Load = 600 kN X=Capacity (resistance)
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