Q3) The characteristic equation of a closed loop system is given as following: P(s) = s4 +5³ +3s² +2s +2 for this system considering the root locus, calculate the imaginary axis crossing points. (Points where root-locus crosses the imaginary axis) a) s = +j√2, -j√3 b) s = +j5,-j5 c) +j√2,-j√2 d) Root locus does not cross the Imaginary Axis
Q3) The characteristic equation of a closed loop system is given as following: P(s) = s4 +5³ +3s² +2s +2 for this system considering the root locus, calculate the imaginary axis crossing points. (Points where root-locus crosses the imaginary axis) a) s = +j√2, -j√3 b) s = +j5,-j5 c) +j√2,-j√2 d) Root locus does not cross the Imaginary Axis
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.61P
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![Q3) The characteristic equation of a closed loop system is given as following:
P(s) = s4 + s³ + 3² +2s + 2
for this system considering the root locus, calculate the imaginary axis crossing points. (Points
where root-locus crosses the imaginary axis)
a) s = +j√2, -j√3
b) s = +j5,-j5
c) +j√2,-j√2
d) Root locus does not cross the Imaginary Axis](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63719a57-3eb4-42a7-a05e-fbc73c4b5890%2Fc424ccf6-12d0-4b80-a0ec-9a38d08d4b3e%2Fnl9vd6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q3) The characteristic equation of a closed loop system is given as following:
P(s) = s4 + s³ + 3² +2s + 2
for this system considering the root locus, calculate the imaginary axis crossing points. (Points
where root-locus crosses the imaginary axis)
a) s = +j√2, -j√3
b) s = +j5,-j5
c) +j√2,-j√2
d) Root locus does not cross the Imaginary Axis
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